25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
Step-by-step explanation:
We have been given the equation
and we are asked to apply the square root property of equality to our given a equation and isolate the variable
First, take the square root of both sides of our equation
<em>THEREFORE, THERE ARE TWO SOLUTIONS FOR OUR GIVEN EQUATION</em>
<em>
</em>
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Why would rare vegetable seeds be that cheap
a.129.6+16.2
= 145.8
b.129.6×16.2
= 2099.52
c.129.6÷16.2
= 8
d.129.6−16.2
= 113.4
e.192.4+14.8
= 207.2
