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Dovator [93]
3 years ago
6

If a stone tower is 15 meters tall and casts a shadow 8 meters long, then how long of a

Mathematics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

32 meters long (please double-check! sometimes ppl make mistakes)

Step-by-step explanation:

the ratio of height to shadow length is 15:8, as established in the first sentence. if both sides of the ratio are multiplied by 4 then the ratio becomes 60:32.

more in depth:

if you think of it as fractions (which ratios can be written as) multiplying both the numerator and denominator by four is the equivalent of multiplying by 4/4 aka 1 so the value still stays the same (one times something is the same thing). since the ratio of height to shadow length is constant we needed to solve for the ratio in which the height is 60, so multiply each side by 4 (aka 60 divided by 15) to find the new ratio, 15(4):8(4) or 60:32. the ratio 60:32 describes height to shadow, so while the height is 60 (said in the problem) then the shadow length is 32. adding units, the answer would be 32 meters.

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3 years ago
What is the slope of a line that passes (-4,2) and (6,8)?
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3 years ago
The 10th term in the sequence is 2560 what is the 11th term in the sequence
joja [24]

Full Question:

The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?

Answer:

the 11 the term is 5120

Step-by-step explanation:

Given

Geometry Progression

4th term = 40

10th term = 2560

Required

11 term.

The nth term of a geometric sequence is calculated as follows

Tₙ = arⁿ⁻¹

For the 4th term, n = 4 and Tₙ = 40

Substitute these in the given formula; this gives

40 = ar⁴⁻¹

40 = ar³. --;; equation 1

For the 10th term, n = 10 and Tₙ = 2560

Substitute these in the given formula; this gives

2560 = ar¹⁰⁻¹

2560 = ar⁹. --;; equation 2

Divide equation 2 by 1. This gives

2560/40 = ar⁹/ar³

64 = r⁹/r³

From laws of indices

64 = r⁹⁻³

64 = r⁶

Find 6th root of both sides

(64)^1/6 = r

r = (2⁶)^1/6

r = 2

Substitute r = 2 in equation 1

40 = ar³. Becomes

40 = a * 2³

40 = a * 8

40 = 8a

Divide both sides by 8

40/8 = 8a/8

5 = a

a = 5.

Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11

So,

Tₙ = arⁿ⁻¹ becomes

Tₙ = 5 * 2¹¹⁻¹

Tₙ = 5 * 2¹¹⁻¹

Tₙ = 5 * 2¹⁰

Tₙ = 5 * 1024

Tₙ = 5120.

Henxe, the 11 the term is 5120

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Answer:

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Answer:

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