All categories

3 years ago

Is 34,557,993 divisible by 3

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

5 0

Answer:

Yes!

Step-by-step explanation:

Diano4ka-milaya [45]3 years ago

3 0

Answer:

Yes, and the answer will be 11,519,331.

Hope it helps!

You might be interested in

Tim Worker expects Social Security benefits of $937 per month. His wife, Mary, is eligible for a wife's benefit of 50 percent of

serg [7]

Answer:

The answer is B: 468.50

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

DE=2x EF=2x-6 DF=3x+5 What is DE

Nataly_w [17]

Answer:

DE=2x you kinda put the answer

Step-by-step explanation:

5 0

3 years ago

Pirate Kenny washes his trousers every five months. He washes his hat every seven months. He washes both his trousers and his ha

Ipatiy [6.2K]

Answer:

If you're going by washes, 6 washes

Step-by-step explanation:

h: 7, 2, 9, 4, 11, 6, 1, 8

t : 5,10,3,8,1,6

6 0

3 years ago

5 positive integers are arranged in ascending order, as follows:

Olegator [25]

Answer:

x = 16

Step-by-step explanation:

Since the numbers are in ascending order, x is the number with the highest value here.

From the arrangement, we can see that the median (the middle number) is the third number which is 9

The mean is the sum of the numbers divided by their count. So we set up the mean and equate to the median

We have this as;

(1 + 9 + 9 + 10 + x)/5 = 9

29 + x = 5(9)

29 + x = 45

x = 45-29

x = 16

5 0

3 years ago

At a carnival, contestants are asked to keep rolling a pair of dice until they roll snake eyes. The number of rolls needed has a

Stells [14]

Answer:

The two numbers of rolls are 25.2 and 46.8.

Step-by-step explanation:

The Chebyshev's theorem states that, if X is a r.v. with mean µ and standard deviation σ, then for any positive number k, we have

$P (|X -\mu| < k\sigma) \geq (1-\frac{1}{k^{2}})$

Here

$(1-\frac{1}{k^{2}})=0.75\\\\\Rightarrow \frac{1}{k^{2}}=0.25\\\\\Rightarrow k=\sqrt{\frac{1}{0.25}}\\\\\Rightarrow k=2$

Then we know that,

$|X - \mu| \geq k\sigma,\\\\ \Rightarrow \mu - k\sigma \leq X \leq \mu + k\sigma$ .

Here it is given that mean (µ) = 36 and standard deviation (σ) = 5.4.

Compute the two values between which at least 75% of the contestants lie as follows:

$P(\mu - k\sigma \leq X \leq \mu + k\sigma)=0.75\\\\P(36 - 2\cdot\ 5.4 \leq X \leq 36 + 2\cdot\ 5.4)=0.75\\\\P(25.2\leq X\leq 46.8)=0.75$

Thus, the two numbers of rolls are 25.2 and 46.8.

8 0

3 years ago