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11111nata11111 [884]
3 years ago
13

A circle has a radius of 5 in. A central angle that measures 150° cuts off an arc.

Mathematics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

Part 1) The exact value of the arc length is \frac{25}{6}\pi \ in

Part 2) The approximate value of the arc length is 13.1\ in

Step-by-step explanation:

ind the circumference of the circle

The circumference of a circle is equal to

C=2\pi r

we have

r=5\ in

substitute

C=2\pi (5)

C=10\pi\ in

step 2

Find the exact value of the arc length by a central angle of 150 degrees

Remember that the circumference of a circle subtends a central angle of 360 degrees

by proportion

\frac{10\pi}{360} =\frac{x}{150}\\ \\x=10\pi *150/360\\ \\x=\frac{25}{6}\pi \ in

Find the approximate value of the arc length

To find the approximate value, assume

\pi =3.14

substitute

\frac{25}{6}(3.14)=13.1\ in

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Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

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Step-by-step explanation:

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C is the point (-301, 601)<br> Does C lie on the straight line passing through A and B?
Marat540 [252]

Answer:

There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.

To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.

Step-by-step explanation:

Suppose the equation of the straight line that passes through E and F is this:

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We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.

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10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.

If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.

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