Answer:
∠ADB=35°
Step-by-step explanation:
Given arc AB = 70°.
we have to find the angle ∠ADB
Here, Angle subtended by arc AB at O is ∠AOB = 70°
By the theorem,
The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
∴ ∠AOB=2(∠ADB)
⇒ ![\angle ADB=\frac{1}{2}\angle AOB=\frac{1}{2}70^{\circ}= 35^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20ADB%3D%5Cfrac%7B1%7D%7B2%7D%5Cangle%20AOB%3D%5Cfrac%7B1%7D%7B2%7D70%5E%7B%5Ccirc%7D%3D%2035%5E%7B%5Ccirc%7D)
hence, angle subtended at the circumference is 35°
Answer:
22/3
Step-by-step explanation:
Make the whole number turn into a fraction, (21/3) and add the numerator (1/3), which the answer would be 22/3
(1) -(5y - 2)= -5y+2
(2) -5 (3n + 1)= -15n - 5
(3) too long to do
Answer:
Area= 32 (formula is: length x width)
Perimeter= 8 + 4 + 8 + 4= 24
Step-by-step explanation:
keeping in mind that a line with a slope of "0" is a horizontal line, Check the picture below.