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Katena32 [7]
3 years ago
7

The first few steps in solving the quadratic equation 8x2 + 80x = −5 by completing the square are shown.

Mathematics
2 answers:
azamat3 years ago
6 0

Answer:

200

Step-by-step explanation:

8 * 25

Elanso [62]3 years ago
3 0

Answer:

d; 200

Step-by-step explanation:

took the quiz

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Find the median for the following data set: 11, 13, 17, 11, 10, 15, 11, 12, 13, 15
vodka [1.7K]

Answer:

A, 12.5

Putting them in order was this:

10, 11, 11, 11, 12, 13, 13, 15, 15, 17

and the median is between 12 and 13, which is 12.5

(Hope that helps you. ^^)

7 0
3 years ago
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A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 20 ft from the path and is kept f
krek1111 [17]

Answer:

0.128rad/sec

Step-by-step explanation:

Let x represent the between the man and the point on the path

θ = the angle

dx/dt = 4 ft/s

dθ/dt = rate is the searchlight rotating when the man is 15 ft from the point on the path closest to the searchlight

tan θ = x/20 ft

Cross Multiply

20tan θ = x

dx/dt = 20sec² θ dθ/dt

dθ/dt = 1/20 × cos² θ dx/dt

dθ/dt= 1/20 × cos² θ × 4

dθ/dt = 1/5 × cos² θ

Note : cos θ = 4/5

dθ/dt = 1/5 × (4/5)²

dθ/dt = 16/125

dθ/dt = 0.128rad/sec

6 0
3 years ago
Find the area of the right triangle. If necessary, round to the nearest tenth
Ad libitum [116K]

Answer:

B. 150 yards

Step-by-step explanation:

Area of a Triangle = .5 * Base * height

So we need the height of the triangle, or the missing side.

We have to use Pythagorean Theorem to solve this:

A^2 + B^2 = C^2

15 ^ 2 + B ^ 2 = 25 ^2

b^2 = 25^2 - 15 ^ 2

b^2 = 625 - 225

b^2 = 400

sqrt (400) = 20

The missing height is 20. Now we plug it into 1/2 * b * H

.5 * 15 * 20

7.5 * 20 = 150

150 Yds

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3 years ago
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joja [24]

Answer:

4.8%

Step-by-step explanation:

28+12=40

40÷100=0.4

1% - 0.4 teachers

0.4×12=4.8

3 0
3 years ago
What is the solution to -1 - 7
mixas84 [53]

Answer:

-8

Step-by-step explanation:

start at -1, move 7 more spots left you get to -8

please hit the heart button :)

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3 years ago
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