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3 years ago

Simplify -7y(4-y) plz also include explanation

Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

Use distributive property
-28y+8y= -20y

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When measuring the length a and the width b of a rectangle, it was found that 5.4< a< 5.5 and 3.6< b< 3.7 (in centim

leva [86]

Answer:

The possible values of the perimeter of the rectangle is between 18 and

18.4 cm ⇒ [18 < perimeter of rectangle < 18.4] cm

Step-by-step explanation:

* Lets explain how to solve the problem

- The perimeter of any quadrilateral is the sum of the length of its

four sides

- The rectangle is a quadrilateral with each two opposite sides are

equal in lengths, then its perimeter = 2l + 2w, where l, w are its

length and width

∵ The the length of the rectangle is a

∵ 5.4 < a < 5.5 cm

∵ The perimeter of the rectangle = 2a + 2b

- Lets multiply the inequality by 2

∴ 5.4 × 2 < a × 2 < 5.5 × 2

∴ 10.8 < 2a < 11 ⇒ (1)

∵ The width of the rectangle is b

∵ 3.6 < b < 3.7 cm

- Lets multiply the inequality by 2

∴ 3.6 × 2 < b × 2 < 3.7 × 2

∴ 7.2 < 2b < 7.4 ⇒ (2)

- Add inequalities (1) and (2)

∵ 10.8 < 2a < 11

+ 7.2 < 2b < 7.4

∴ 18 < 2a + 2b < 18.4

∵ 2a + 2b represents the perimeter of the rectangle

∴ The possible values of the perimeter of the rectangle is between

18 and 18.4 cm ⇒ [18 < perimeter of rectangle < 18.4] cm

7 0

3 years ago

Cuánto es 6321 dividido 694?

Maksim231197 [3]

Answer:

9.10806916427

Step-by-step explanation:

6 0

3 years ago

Helpp the topic is about limits

erik [133]

Since we want to find the value of k where the limit exists, set both equations equal to each other. Then substitute x = -1 in for each equation to find k.

$kx - 3 = {x}^{2} + k$

1. Set both equations equal.

$- k - 3 = 1 + k$

2. Substitute x = -1.

$- 3 = 1 + 2k$

3. Solve for k by adding k to both sides. Continue the process of solving the equation.

$- 4 = 2k$

$k = - 2$

Thus, k = -2. Check by graphing the function.

8 0

2 years ago

Plz help question below

hammer [34]

Plan B. to me is he obvious answer.

4 0

3 years ago

The weight of tigers follow a normal distribution with a mean of 220 kg and a SD of 30 kg. 1) If we randomly select a tiger, wha

mylen [45]

Answer:

0.89736

Step-by-step explanation:

We solve this question using z score formula

Z score = x - μ/σ

x = raw score

μ = population mean

σ = population standard deviation

Hence,

x = 258, μ = 220, σ = 30

Z = 258 - 220/30

=1.26667

Probability value from Z-Table:

P(x<258) = 0.89736

Therefore, the probability that his weights is less than 258 kg is 0.89736

6 0

3 years ago