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1 year ago

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What is 150% of 3000? Round to the nearest hundredth

1 answer:

marin [14]1 year ago

4 0

We want to find 150% of 3000. since 150% is greater than 100%, it is expected that 150% 0f 3000 will also be greater than 3000.

$150\text{\% of 3000 }=\frac{150}{100}\times3000=4500$

Therefore, 150% of 3000 is equal to 4500.

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Dylan runs 4 laps around a track in 16 minutes.

vichka [17]

A. 4 minutes per lap

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3 years ago

what �is the equation of a line that is perpendicular to the line y = − 2 5 x − 5 y = - 2 5 x - 5 and passes thr

gladu [14]

Answer:

$y=\frac{1}{25}x-\frac{31}{25}$

Step-by-step explanation:

$y=-25x-5$

You can get the gradient of the line perpendicular to this as you know the products of their gradients will be -1.

$-25*m_{perpendicular}=-1\\m_{perpendicular}=\frac{1}{25}$

We have a gradient, and a point (6, 1), so we can now substitute our known values into the line equation.

$(y-y_0)=m(x-x_0)$

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4 years ago

Jakob wants to invite 20 friends to his birthday, which will cost his parents $250. If he decides to invite 15 friends instead,

timofeeve [1]

Answer:

$187.50

Step-by-step explanation:

250/25= $12.50 per person

12.5 x 15= $187.50

4 0

3 years ago

Read 2 more answers

The chair of the operations management department at Quality University wants to construct a p-chart for determining whether the

sasho [114]

Answer:

Prof B and Prof D

Step-by-step explanation:

Step-by-step explanation:

From the question we are told that

Sample size 100

Instructor Number of Failures

Prof. A 13

Prof. B 0

Prof. C 11

Prof. D 16

Confidence level= 0.95

From Z table

Z=1.96

Generally proportion for failure is mathematically given as

$Proportion\ of\ Failure\ P=\frac{Number\ of\ Failure\ N}{Sample\ size\ S}$

$P=\frac{N}{S}$

For Prof A

$P_A=\frac{N_A}{S}$

$P_A=\frac{13}{100}$

$P_A=0.13$

For Prof B

$P_B=\frac{N_B}{S}$

$P_B=\frac{0}{100}$

$P_B=0$

For Prof C

$P_C=\frac{N_C}{S}$

$P_C=\frac{11}{100}$

$P_C=0.11$

For Prof D

$P_D=\frac{N_D}{S}$

$P_D=\frac{16}{100}$

$P_D=0.16$

Generally the average proportional failure is mathematically given as

$P_a_v_g=\frac{0.13+0+0.11+0.16}{4}$

$P_a_v_g=0.10$

Therefore having this we calculate for the control limits

Generally the upper control limit UCl is mathematically given as

Upper control limits:

$UCL =P_a_v_g +Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 +1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 +1.96*0.03$

$UCL =0.1 +0.0588$

$UCL =0.1588$

Generally the upper control limit UCl is mathematically given as

Lower limit control limits:

$UCL =P_a_v_g _Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 -1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 -1.96*0.03$

$UCL =0.1 -0.0588$

$UCL =0.0412$

Therefore the Range is 0.0412 to 0.1588

Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options

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bixtya [17]

I dont even know how to start answering that last question...

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