The interpretation of the given question is as follows:
Use the given inverse to solve the system of equations
The inverse of ![\left[\begin{array}{ccc}1&-1&1\\0&2&1\\3&-8&0\end{array}\right] is \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%261%5C%5C0%262%261%5C%5C3%26-8%260%5Cend%7Barray%7D%5Cright%5D%20%20%20is%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-8%268%263%5C%5C-3%263%261%5C%5C6%26-5%26-2%5Cend%7Barray%7D%5Cright%5D)
x =
y =
z =
Answer:
x = - 1.5
y = - 0.5
z = - 5
Step-by-step explanation:
Using the correlation of inverse of matrix AX = B to solve the question above;
AX = B
⇒ A⁻¹(AX) = A⁻¹ B
X = A⁻¹ B
So ;
X = A⁻¹ B
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D)
![\left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-8%268%263%5C%5C-3%263%261%5C%5C6%26-5%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D)
![\left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%5C%5C%20-6%5C%5C-%20%5Cdfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-8%2A-6%29%2B%288%2A-6%29%2B%283%2A-%5Cdfrac%7B1%7D%7B2%7D%29%5C%5C%28-3%2A-6%29%2B%283%2A-6%29%2B%281%2A-%5Cdfrac%7B1%7D%7B2%7D%29%5C%5C%286%2A-6%29%2B%285%2A-6%29%2B%28-2%2A%20-%20%5Cdfrac%7B1%7D%7B2%7D%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%2848%29%2B%28-48%29%2B%28%5Cdfrac%7B-3%7D%7B2%7D%29%5C%5C%2818%29%2B%28-18%29%2B%28%5Cdfrac%7B-1%7D%7B2%7D%29%5C%5C%28-36%29%2B%2830%29%2B%281%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(\dfrac{-3}{2})\\(\dfrac{-1}{2})\\(-5)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28%5Cdfrac%7B-3%7D%7B2%7D%29%5C%5C%28%5Cdfrac%7B-1%7D%7B2%7D%29%5C%5C%28-5%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-1.5\\-0.5\\ -5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1.5%5C%5C-0.5%5C%5C%20-5%5Cend%7Barray%7D%5Cright%5D)
Answer:
First question, x= 10^10.
Second question is 10!. or 362880
Step-by-step explanation:
First Question:
Simple logx has a base of 10, i.e log10 x,
the question will be 10 = log10 x,
when taking the base "10" from the right side to the left, the number on the left side becomes the power of the base, in this case 10 from the right will be base and 10 from the left will power and log will vanish.
x=10^10.
Another example with different numbers
Y=logx if Y= 12, What is x?
The base is ten when not given,so:
12=logx
10^12=x
Second Question;
simple multiplication just multiply the numbers.
10! is pronounced as 10 factorial,
5! will be 5x4x3x2x1=120
try and see if it =0
Step-by-step explanation:
This deals with factoring multi-variable polynomials.
You should try to retake the picture can’t c anything
Hhey it should be
Random selection
just because they all have a chance :) hope it helps
