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3 years ago

7

Challenge #2 Press "Deal" to receive your cards. Drag cards from your hand to the red and blue areas. GOAL: Create two groups of

cards with the SAME SUM using as many cards as possible.

1 answer:

Novosadov [1.4K]3 years ago

8 0

Answer:

Can you explain what the press deal and recieve cards means?

Step-by-step explanation:

You might be interested in

Which inequality corresponds to the sentence "five less than the product of a number and 6 is at least 8"?

Roman55 [17]

Answer:

6x - 5 ≥ 8

Step-by-step explanation:

Which inequality corresponds to the sentence "five less than the product of a number and 6 is at least 8"?

The inequality sign of

a) At least = greater than or equal to = ≥

Let us represent the number as = x

Hence: "five less than the product of a number and 6 is at least 8" can be written as:

= x × 6 - 5 ≥ 8

= 6x - 5 ≥ 8

5 0

3 years ago

Solve for x.........

True [87]

Answer:

9x-25 = 5x+7 (reason: opposite sides of a parallelogram are equal)

4x-25 = 7

4x = 7+25

4x = 32

x = 8

8 0

3 years ago

Simplify: 1(-3.86 + 6.82)| + |(4.02 - 12.45)||

Yuki888 [10]

Answer:

11.39

Step-by-step explanation:

-3.86+6.82=2.96

abs(2.96)=2.96

----------------------

4.02-12.45=-8.43

abs(-8.43)=8.43

-----------------------

1(2.96)+8.43=2.96+8.43=11.39

6 0

3 years ago

What is the solution to the equation 8q + 4 = 20

nadya68 [22]

8q+4=20
8q=16
q=2
hope this helps!

7 0

3 years ago

The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\lambda x}$

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

In all 3 cases, we want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = 1 - e^{-5\lambda}$

(a) lambda=.5

$P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821$

(b) lambda=0.9

$P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111$

(c) lambda=1.1

$P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041$

7 0

4 years ago