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Charra [1.4K]
3 years ago
15

Which set of values makes the inequality x + 2 ≥ 0 true?

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

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C. X = 16

To solve, add 7 to both sides and multiply by the reciprocal of \frac{-9}{8}, \frac{-8}{9}.

( \frac{-9}{8} ) X - 7 = -25



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Complete the two column proof.
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Reason a) Alternate interior angles of parallel lines are congruent.

Statement b) Line RQ is congruent to line RQ.

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3 years ago
Use 6.84 days as a planning value for the population standard deviation. a. Assuming 95% confidence, what sample size would be r
vlabodo [156]

Answer:

The sample size required is n = (\frac{1.96*6.84}{M})^2, in which M is the desired margin of error. If n is a decimal number, it is rounded up to the next integer.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Use 6.84 days as a planning value for the population standard deviation.

This means that \sigma = 6.84.

What sample size would be required to obtain a margin of error of M days?

This is n for the given value of M. So

M = z\frac{\sigma}{\sqrt{n}}

M = 1.96\frac{6.84}{\sqrt{n}}

M\sqrt{n} = 1.96*6.84

\sqrt{n} = \frac{1.96*6.84}{M}

(\sqrt{n})^2 = (\frac{1.96*6.84}{M})^2

n = (\frac{1.96*6.84}{M})^2

The sample size required is n = (\frac{1.96*6.84}{M})^2, in which M is the desired margin of error. If n is a decimal number, it is rounded up to the next integer.

8 0
3 years ago
Find the lateral area for the regular pyramid.<br> L. A. =
IRINA_888 [86]

Answer:

Step-by-step explanation:

slant height=√(3²+1²)=√10

L.A=4×1/2×2×√10=4√10

8 0
3 years ago
Find the median for each of the following distributions
nasty-shy [4]

a) 1 , 4 , 4 , 5 , 6 —> median ; 4

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d) 10 , 13 , 13 , 17 , 19 , 19 , 21 —> median ; 17

e) 0.6 , 0.6 , 1.3 , 1.5 , 2.1 , 2.3 , 3.2 —> median ; 1.5

f) 0.1 , 0.4 , 0.6 , 1.8 , 2.2 , 2.5 , 2.7 —> median ; 1.8

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h) 2 , 2 , 5 , 6 , 8 , 9 , 9 , 9 , 12 , 13 , 13 —> median ; 9

I hope I helped you^_^

7 0
3 years ago
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