<u>Answer:</u>
The 4th term of the geometric sequence with = 5 and ratio (multiplier) = -3 is -135
<u>Solution:</u>
Given that, first term a of a G.P = 5 and common ratio ( r ) = -3 for an geometric progression.
We have to find the 4th term of the above given geometric progression
We know that, nth term of an G.P is given by
So, now, 4th term is
hence, the 4th term of the given G.P is -135
Answer:
12 m
Step-by-step explanation:
The path of a football has been modeled by the equation:
where h represents the height and d represents the horizontal distance.
When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.
=>
∴ d = 0 m
and
10d - 120 = 0
=> d = 120 / 10 = 12 m
There are two solutions for d when h = 0 m.
The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.
The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m