Answer:
j=46
Step-by-step explanation:
34=j-12
add 12 to 34 to isolate j
the answer to that is 46
j=46
Answer:
50
Step-by-step explanation:
50 / 10 = 5
5 x 3 = 15
3 x + 7 = 2
3 x = 2 - 7
3 x = - 5
x = - 5/3
3 ( -5/3) + 7 = - 15/3 + 7 = - 5 + 7 = 2
Answer:
B 126, 126+7 equals 18 so thats the answer
Answer:
6*8=48 groups with elements of order 7
Step-by-step explanation:
For this case the first step is discompose the number 168 in factors like this:
And for this case we can use the Sylow theorems, given by:
Let G a group of order where p is a prime number, with and p not divide m then:
1)
2) All sylow p subgroups are conjugate in G
3) Any p subgroup of G is contained in a Sylow p subgroup
4) n(G) =1 mod p
Using these theorems we can see that 7 = 1 (mod7)
By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.
Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.
So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168