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Anika [276]
3 years ago
13

A truck travels from a factory to a gas station in 5 minutes. It stops at the gas station for 1 minute. The truck then returns t

o the factory in 4 minutes. Which graph best represents the distance, y, in miles, of the truck from the factory for a certain amount of time, x, in minutes?
Mathematics
1 answer:
aksik [14]3 years ago
5 0

Answer:

Step-by-step explanation:

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Delvig [45]

Answer:

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Step-by-step explanation:

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3 years ago
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A man who is 5feet 9inches tall casts a shadow of 8feet 6inches. assuming that the man is perpendicular to the ground,what is th
s344n2d4d5 [400]

The angle of elevation from the end of the shadow to the top of the man's head will be 34.077°.

<h3>What is a right-angle triangle?</h3>

It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function. The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

A man who is 5feet 9inches tall casts a shadow of 8feet 6inches.

Assuming that the man is perpendicular to the ground.

5 ft 9 in = 69 in

8 ft 6 in = 102 in

Then the angle of elevation from the end of the shadow to the top of the man's head will be

tan θ = 69/102

θ = tan ⁻¹ (0.676)

θ = 34.077°.

More about the right-angle triangle link is given below.

brainly.com/question/3770177

#SPJ1

5 0
2 years ago
The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ &amp; Johnson​ (JNJ) stock for
egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
  • The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

4 0
2 years ago
Carter was given a box of assorted chocolates for his birthday. Each night, Carter treated himself to some chocolates. Carter at
yanalaym [24]
C(t) = 30 - 5t ur very much welcome
3 0
3 years ago
6th grade math help me pleaseee
Likurg_2 [28]

Answer:

-7.96

Step-by-step explanation:

I used a calculator

6 0
3 years ago
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