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2 years ago

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a map that contains cities A and b is shown the map used it uses a scale of 1 inch:20 mi if you are making a map that uses a sca

le of 3 inch: 35 mi how far apart are cities A and b on your mat

1 answer:

OverLord2011 [107]2 years ago

3 0

Answer:

Step-by-step explanation:

Hi

You might be interested in

Find the vertical asymptotes. 2x2 + 7x + 6 y = 3x2 + 10x - 8 * = [ [?], x=

Llana [10]

Answer:

$-\frac{77}{24}$

Step-by-step explanation:

1. rewrite the equation in standard form: $4\cdot \frac{3}{2}\left(y-\left(-\frac{41}{24}\right)\right)=\left(x-\left(-\frac{3}{2}\right)\right)^2$

2. find (h,k), the vertex. the vertex is $\left(h,\:k\right)=\left(-\frac{3}{2},\:-\frac{41}{24}\right)$

3. find the 'focal length' of the parabola - the focal length is the distance between the vertex and the focus. from the vertex we can see that the focal length, p, = 3/2

4. Parabola is symmetric around the y-axis and so the asymptote is a line parallel to the x-axis, a distance p from the $\left(-\frac{3}{2},\:-\frac{41}{24}\right)$ y coordinate which is at $-\frac{41}{24}\right)$ . Set up the equation:

$y=-\frac{41}{24}-p$

5. substitute and solve:

$y=-\frac{41}{24}-\frac{3}{2}$

$y = -\frac{77}{24}$

hope this helps, ask me questions if you still don't understand.

8 0

3 years ago

Suppose the round-trip airfare between Philadelphia and Los Angeles a month before the departure date follows the normal probabi

QveST [7]

Answer:

52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 387.20, \sigma = 68.50$

What is the probability that a randomly selected airfare between these two cities will be between $325 and $425?

This is the pvalue of Z when X = 425 subtracted by the pvalue of Z when X = 325. So

X = 425

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{425 - 387.20}{68.50}$

$Z = 0.55$

$Z = 0.55$ has a pvalue of 0.7088

X = 325

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{325 - 387.20}{68.50}$

$Z = -0.91$

$Z = -0.91$ has a pvalue of 0.1814

0.7088 - 0.1814 = 0.5274

52.74% probability that a randomly selected airfare between these two cities will be between $325 and $425

7 0

2 years ago

Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac

Brums [2.3K]

Answer: The population will be 408,000 people.

Step-by-step explanation:

So in 2000 there were 200,000 people and it started to grow 8% every year so up to 2013.

so find 8% of 200,000 and then multiply it by the the number of years.

8% * 200,000 = 16,000

Find the difference between the years.

2013 - 2000 = 13 years

13 * 16000 = 208000 This is the amount of new people from 2000 to 2013 so add it to the original population.

208,000 + 200,000 = 408,000

5 0

3 years ago

Draw an area model to solve 549÷ 3

Allisa [31]

Answer:

183

Step-by-step explanation:

i cant draw an actual model but 549/3 = 183

7 0

2 years ago

BE is a midsegment, Find the value of x. Please

Scrat [10]

Answer:

x10

Step-by-step explanation:

BE=1/2 * CD

x=CB/2

x=20/2

x=10

8 0

2 years ago