y = -
(x - 5)² + 4
the equation of a quadratic in standard form is
y = a(x - h)² + k ( where (h , k ) are the coordinates of the vertex and a is a multiplier )
given vertex = ( 5, 4 ) then
y = a(x - 5)² + 4 ( to find a substitute (7 , 1 ) into the equation )
1= 4a + 4
4a = - 3 ⇒ a = - 
y = -
(x - 5)² + 4 ← ( in vertex form )
The function has neither because it goes infinitely up and infinitely down
Answer:
the x intercept=(-6,0) and y intercept=(0,14)
Step-by-step explanation:
i used math may but put the m as w, it works