Answer:
Yes, A KLP can be reflected across the line containing KP and then translated so that Pis mapped to M.
Step-by-step explanation:
The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.
A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.
If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.
Answer:
23
Step-by-step explanation: You have to do 5x5 because 5^2 mans there is two fives. Then you just subtract two
5x5=25
25-2=23
45x20x18=16,200
350x9=3150
total = 19,350
Answer: 1.3931 E 12
Step-by-step explanation:
plugged into the calculator and got this!
De Moivre's Theorem states that if a complex number is written in the polar coordinate form [ r (cosθ +
sinθ)] and you raise it to the power n, then this can be evaluated by raising the modulus (r) to the power and multiply the argument (θ) by the power. This therefore would give r ⁿ [cos (nθ) +
sin (nθ)].
let A = ∛ <span>(8 cos (4π / 5) + 8 i sin (4π / 5))
</span>⇒ A = ∛ <span>(8 [cos (4π / 5) + i sin (4π / 5)])
</span>
Now by applying De Moivre's Theorem,
⇒ A =
[cos (
×
) +
sin (
×
)
⇒ A = 2 [ cos (
) +
sin (
)
⇒ A = 2 [0.0117 +
0.01297 ] rads