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3 years ago

13

Given triangle ABC with AB = 3 , BC = 5 , and CA = 6 . X is the midpoint of AC and is the midpoint of CB. What is the relationsh

ip between XY and AB?
A) congruent
B) parallel
C) perpendicular
D) similar

1 answer:

Helga [31]3 years ago

7 0

parallel accroding to the mid point theorems.

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A zoo has 15 Emperor penguins. The Emperor penguins make up 30% of all the penguins at the zoo

Otrada [13]

Answer:

Step-by-step explanation:

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so 30% of all the penguins is 15

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x = 15 / 0.30

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What is the area of a circle whose equation is (x-3)² + (y + 1) ² =81?

kupik [55]

Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle:

$\frac{(x-x_{1})^2}{r^2}+ \frac{(y-y_{1})_^2}{r^2}=1$

Where $(x_{1}, y_{1})$ is the centre of the circle. In this case, we don't need to know the centre. Just the radius.

Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81.

$\frac{(x-3)^2}{81}+ \frac{(y+1)^2}{81}=1$

Great! We now know the radius of the circle. It is $\sqrt{81}$ because it is the bottom fraction. Now we know that the radius is 9.

So now lets input this into the area of circle formula:

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You can convert that into a decimal if you wish.

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~Cam943, Moderator

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How can the figure below be changed so that it has exactly one lines of symmetry?

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Answer:

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rusak2 [61]

You forgot to mention the graph.
So, I make the graph of both given functions and you will compare your graph with them.

First, y= -x-1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.

Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.

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