Answer:
50%
Explanation:
Lets denote the freckle allele as "F" and the no freckle allele as "f"
Freckles are dominant to no freckles. Grace has freckles, meaning she must have one "freckle" allele (either FF or Ff). Her dad does not, meaning he has two "no freckle" alleles (ff). Grace has to have inherited one allele of her two alleles from her father, meaning she has to be heterozygous (Ff).
Trey has no freckles, meaning he must be ff. Therefore, the cross of their genotypes would be Ff x ff. The punnett square below shows the outcomes:
<h2><u>
F f </u></h2><h2>
f Ff ff</h2><h2>
</h2><h2>
f Ff ff</h2>
Half of their kids will have freckles (Ff), and half will not (ff), meaning 50% of their possible kids would look like Trey
Answer;
Ligase enzyme
Ligase enzyme is the enyzme that connects the new bases to the old bases in the DNA template.
Explanation;
Ligase enzyme plays important roles in the process of DNA replication and DNA repair.
It seals repairs in the DNA, it seals recombination fragments, and it connects Okazaki fragments.
It facilitates the joining together of the DNA strands by catalyzing the formation of phoshodiester bond.
Depending on the F1 generation (parent) phenotype we can determine whether or not it is homozygous or heterozygous. Also, check to if the F2 grey seeded plant is a mixture of Black and white or if grey is a dominant color. If it is a mixture, it would make it heterozygous. If not and Grey is domminant it would make it homozygous.
