Answer:
The value of is equal to 
Step-by-step explanation:
we know that
-----> by alternate exterior angles
solve for k
9514 1404 393
Answer:
63
Step-by-step explanation:
The number of seats in a row will give an arithmetic sequence:
6, 9, 12, 15, ...
The first term is 6; the common difference is 3. The general term is ...
an = a1 +d(n -1) . . . . . . n-th term of sequence with first term a1, difference d
The 20th term of the sequence is ...
a20 = 6 +3(20 -1) = 6 +57 = 63
There would be 63 seats on the 20th row.
You subtract the numbers 7,801 and 4890
The answer is 2,911
16 squared = 256
14 squared = 196
256 + 196 = 452.
First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
