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alex41 [277]
3 years ago
5

Can someone please help me with this!!!!! 2/5 ÷ 8 1/2 = ?

Mathematics
2 answers:
Harman [31]3 years ago
8 0
You should get 4/85
pav-90 [236]3 years ago
7 0
The answer would be 4/85


1. 2/5 ÷ 8 * 2 + 1  over 2

2. 2/5 ÷ 16 + 1 over 2

3. 2/5 ÷ 17/2

4. 2/5 * 2/17

5. 2 * 2 over 5 * 17

6. 4 over 5 * 17

7. finally 4/85
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The length of a rectangle 8 more than the width .the area is 513 square inches .find the length and width of the rectangle
Pani-rosa [81]

Answer:

width =19 inches

length= 27 inches

Step-by-step explanation:

Let width be w inches so according to given scenario as length is 8 more than width so the equation becomes

l=8+w inches (Equation 1)

Area of Rectangle= L*w

Area= 513

L*w=513    (Equation 2)

Putting l's value from equation 1 in equation 2

(8+w)w=513

w^2+8w-513=0

Making Factors

w^2+27w-19w-513=0

w(w+27)-19(w+27)=0

(w-19)(w+27)=0

w=19, w=-27

as width cannot be negative so if we only consider w=19 then

l=8+19

l=27

3 0
3 years ago
Choose which one you believe doesn't belong.
vodka [1.7K]

Answer:

65

All the other numbers if you add up their digits it is 8.

1 + 7 = 8

2 + 6 = 8

4 + 4 = 8

6 + 5 = 11

26

Is only number divisible by 13.

44 is only divisible by 11

Step-by-step explanation:

3 0
3 years ago
The hypotenuse of the right triangle is 5y inches long. The lengths of the legs are x + 8 and x + 3 inches. If the perimeter of
Zolol [24]

Answer: 35 inches.

Step-by-step explanation:

We know that:

hypotenuse = 5*y in

cathetus 1 = (x + 8) in

cathetus 2 = (x + 3) in

The perimeter of the triangle is 76 inches, then:

5*y + (x + 8) + (x + 3) = 76

5*y + 2*x + 13 = 76

We also know that the length of the hypotenuse minus the length of the shorter leg is 17 in.

The shorter leg is x + 3, then:

5*y - (x + 3) = 17

Then we have the equations:

5*y + 2*x + 11 = 76

5*y - (x + 3) = 17

With only these two we can solve the system, first we need to isolate one of the variables in one of the equations, i will isolate x in the second equation.

x = 5*y  - 3 - 17 = 5*y - 20

x = 5*y - 20

Now we can replace this in the other equation, we get:

5*y + 2*x + 11 = 76

5*y + 2*(5*y - 20) + 11 = 76

15*y - 40 + 13 = 76

15*y - 29 = 76

15*y = 76 + 29 = 105

and remember that the hypotenuse is equal to 5*y, then we want to get:

3*(5*y) = 105

5*y = 105/3 = 35

5*y = 35

Then te length of the hypotenuse is 35 inches.

6 0
3 years ago
What is the point-slope form of a line with slope 6 that contains the same point (1,2)
garri49 [273]
Step 1: Create an equation with a slope of 6
y=6x+b

Step 2: Substitute x and y by with the point (1,2) and solve the equation for b
y=6x+b
2=6(1)
2=6
2=6+b
b=-4

Step 3: Substitute -4 for b in the equation
y=6x+b
y=6x+(-4)
y=6x-4

The equation that has a slope of 6 and passes through the point (1,2) in point-slope form:
y=6x-4
3 0
3 years ago
The length of a rectangle is twice its width. if the area of the rectangle is 50 yds2 , find its perimeter
Law Incorporation [45]
Hello : 
x : length     y :<span> width
</span>xy = 50 ...(1)
x = 2y ...(2)
dubsct in (1) : 
(2y)(y) = 50
y² = 25
y = 5
x = 10

7 0
3 years ago
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