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3 years ago

5x +6y = -6

Mathematics

1 answer:

nadezda [96]3 years ago

3 0

Answer:

(-6,4)

Step-by-step explanation:

If this is the system of equations here is how:

solve for 1 vairuble in the first equation, and plug that it to the other.

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What is the point-slope form of a line with slope 3 that contains the point (2,1)?

Serjik [45]

Answer:

A) $y-1=3(x-2)$

Step-by-step explanation:

Point-slope formula.

$y-y_1=m(x-x_1)$

Given.

Slope (m) = 3

Points (x, y) = (2, 1)

8 0

3 years ago

What are the solutions of 3x^2-x+4=0

guajiro [1.7K]

3x² -x+4=0

We can use quadratic formula
a=3, b= -1, c=4
$x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} 
\\ \\ x= \frac{1+/- \sqrt{1-4*3*4} }{2*3} 
\\ \\ x = \frac{1+/- \sqrt{-47} }{6} 

This equation does not have real roots, it has only 2 imaginary roots.$

$x= \frac{1+ \sqrt{47}i }{6} 
\\ \\ x= \frac{1- \sqrt{47}i }{6}$

6 0

3 years ago

huong and kathyrn each day impeoved their yards by planting rose bushes and ornamental grass. they bought their supplies from th

marta [7]

Answer:

One rose bush = $3

One bunch of ornamental grass = $4

Step-by-step explanation:

We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

$14r+7g=70\\5r+14g=71$

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

$(*-2)14r+7g=70\\5r+14g=71\\-------\\-28r-14g=-140\\5r+14g=71\\--------\\-23r=-69\\r=\frac{-69}{-23}=3$

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

$14r+7g=70\\14(3)+7g=70\\42+7g=70\\7g=70-42\\7g=28\\g=\frac{28}{7}=4$

Thus, 1 bunch of ornamental grass is $4.

5 0

3 years ago

Modern car company has come out with a new car model. Market analysts predict that 4,600 cars will be sold in the first month an

Arte-miy333 [17]

The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars

<h3>Arithmetic sequence</h3>

First month, a = 4,600 cars
Common difference, d = -50 cars

First five terms;

a = 4,600

a + d = 4600 + (-50)

= 4600 - 50

= 4,550

a + 2d

= 4600 + 2(-50)

= 4600 - 100

= 4,500

a + 3d

= 4,600 + 3(-50)

= 4,600 - 150

= 4,450

a + 4d

= 4600 + 4(-50)

= 4,600 - 200

= 4,400

cars predicted for the twelfth month.

a + 11d

= 4600 + 11(-50)

= 4600 + 550

= 4,050

Total predicted number of sold cars for the first year:

Sn = n/2{2a + (n - 1)d }

= 12/2{2×4600 + (12-1)-50}

= 6{9200 + 11(-50)}

= 6(9,200 - 550)

= 6(8,650)

= 51,900 cars

Learn more about arithmetic sequence:

brainly.com/question/6561461

#SPJ1

7 0

2 years ago

Cindy has 30 meters of fencing. She

bogdanovich [222]

The run can be made 11 meters long

3 0

3 years ago