The expressions for the width, W, and area, A, of the rectangle in terms of L are:
- W =
- L - A =
![\frac{13L - L^{2} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B13L%20-%20L%5E%7B2%7D%20%7D%7B2%7D)
The expression for the perimeter of a rectangle is given as:
P = 2(L + W)
where L is its length and W its width
a. Given that the perimeter of the rectangle is 13 feet, then;
13 = 2(L + W)
divide through by 2
= L + W
So that;
W =
- L
The required formula for the width as a function of L is: W =
- L
b. Area of a rectangle can be expressed as;
A = L * W
substitute the expression for width in that of area to have
A = L * (
- L)
=
L - ![L^{2}](https://tex.z-dn.net/?f=L%5E%7B2%7D)
A = ![\frac{13L - L^{2} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B13L%20-%20L%5E%7B2%7D%20%7D%7B2%7D)
The expression for the area A is: A = ![\frac{13L - L^{2} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B13L%20-%20L%5E%7B2%7D%20%7D%7B2%7D)
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Answer: C. 5(6) + 0.65y
Step-by-step explanation:
Process of elimination.
65% of y = 0.65y
A has 65y, completely incorrect.
B has 6y, also completely incorrect.
<u>C has 0.65y, correct.</u>
D has 1.65y, also completely incorrect.
X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer: 1
Step-by-step explanation:
You are welcome :)
Answer:
14/15
Step-by-step explanation:
simple
3/5 + 1/3= 14/15