All categories

3 years ago

Which statement best describes why the value of the car is a function of the number of years since it was purchased?

Mathematics

1 answer:

Scrat [10]3 years ago

7 0

Answer:

Step-by-step explanation:

The definition of a function is that any input will only have one output. Here, the input is the number of years, and the output is the value of the car. We know this because the question is asking why the value of the car is a function of the number of years. Therefore, based on the number of years, the value of the car is given.

Going back to the definition of a function, we can apply this year to say that any number of years will only have one car value. Another way to say this is that each time is associated with exactly one car value.

You might be interested in

The perimeter of a rectangle is 64 units. Can the length X of a rectangle be 20 units when it's width y is 11 units

Blababa [14]

Nope. Perimeter = sum of all sides

P = 20 + 11 + 20 + 11 = 62 and not 64

So, it is not possible.

4 0

3 years ago

I need help on this question!

lord [1]

Answer:

If A = 8, B = 5

If A = 20, B = 3

Step-by-step explanation:

4x²(2x³ + 5x)

8x⁵ + 20x³

If A = 8, B = 5

If A = 20, B = 3

4 0

3 years ago

If you place $1,000.00 in a savings account with an interest rate of 5.25%/month, how much should you earn in interest at the en

Doss [256]

It's al little over 190. you just divide the 1000 by the 5.25%.

4 0

3 years ago

Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B

labwork [276]

Answer:

$x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

Step-by-step explanation:

we are given that $x^3-9x+2x^2-18$

w are sked to step by step factorise the above polynomial

$\left(x^3+2x^2\right)+\left(-9x-18\right)$

$-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)$

$-9x-9\cdot \:2$

$-9\left(x+2\right)$

$\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)$

$-9\left(x+2\right)+x^2\left(x+2\right)$

$\left(x+2\right)\left(x^2-9\right)$

$x^2-9:\quad \left(x+3\right)\left(x-3\right)$

$x^2-9$

$\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2$

$=x^2-3^2$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$x^2-3^2=\left(x+3\right)\left(x-3\right)$

Hence

$x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)$

a) The jay mistake was he did not factorise $x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

8 0

3 years ago

Read 2 more answers

Can someone solve these simultaneous equations and explain the way to do this easily:

N76 [4]

The easiest way to solve this system of equations is by elimination. Both equations have a 3x term, so we can basically subtract the equations to cancel the 3x. Then we will be left with a single variable to solve for.

(3x + y = -4)
-(3x -4y = 6)

Distribute the negative:

(3x + y = -4)
(-3x + 4y = -6)

Now add the equations together term by term:

0x + 5y = -10

5y = -10

y = -2

Plug y = -2 into either equation to find x.

3x + (-2) = -4

3x = -2

x = -2/3

So the answer as an ordered pair is (-2/3, -2)

8 0

3 years ago