-10 ≥ 2x + 14
-24 ≥ 2x [subtract 14 from both sides]
2x ≤ -24 [read right to left]
x ≤ -12 [divide both sides by 2]
Check:
Let x = -13 (It is ≥ -12)
Is this true: -10 ≥ 2(-13) + 14 ?
-10 ≥ -26 + 14 ?
-10 ≥ -14 ?yes
Let x = -11 (it is not ≥ -12)
Is this false:: -10 ≥ 2(-11) + 14 ?
-10 ≥ -22 + 14 ?
-10 ≥ -8 ?yes
You can substitute in values of x into the given equation y = 4x^2 - 1 and determine their corresponding y values. Then see which of these points correspond to the graphs q, r, s, t.
For example, if x = 0, then
y = 4(0)^2 - 1
y = -1
The point would be (0, -1)
If x = 1, then
y = 4(1)^2 - 1
y = 4 - 1
y = 3
The point would be (1, 3)
The only graph with points (0, -1) and (1, 3) is graph t.
Answer:
1) The function f(x) has a higher y-intercept.
Step-by-step explanation:
From the data given, I can conclude that g(x) is a linear function. That means that when x=0, y would be 0, and g(x) would thus have a lower y-intercept.
