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Zarrin [17]
3 years ago
9

I'M IN A TEST!!!! PLEASE HELP BUT PLEASE DON'T GUESS!!!!

Mathematics
2 answers:
max2010maxim [7]3 years ago
5 0

Answer:

325 animals

Step-by-step explanation:

All you have to do is add all of the animals together.

85+70+65+60+45= 155+125+45=155+170=325 animals

If this helps please mark as brainliest

irga5000 [103]3 years ago
4 0

Answer:

325

Step-by-step explanation:

Fish=45

Birds=65

Dogs=85

Cats=70

Other=60 which is 325 & i double checked for you :)

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Jack wants to plant a border of flowers in the shape of an arc along the edge of a circular walkway. of the circle has a radius
Jet001 [13]
To solve this problem you must apply the proccedure shown below:

 1. You must apply the formula for calculate the arc length, which is:

 arc length=(angle)(radius)

 2- As you can see, <span>the circle has a radius of 5 yards and the angle subtended by the arc measures 1 1/2 radians. Therefore, you have:
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 The angle is:

 1 1/2 radians=1.5 radians

 3. When you susbtitute these values into the formula, you obtain:

 arc length=(1.5 radians)(5 yards)
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6 0
3 years ago
On average, a commercial airplane burns about 3.9 × 10³ milliliters of gasoline per second. There can be as many as 5.1 × 10³ ai
Pavel [41]
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5 0
3 years ago
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You spin the spinner twice. Find the probability of spinning a 2 then a number greater than 2. ( 6 spaces)
Alina [70]

Answer:

1/9

Step-by-step explanation:

You take 1/6 times 4/6 which equals 1/9.

Hope that helped! :)

3 0
3 years ago
Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid
Gnom [1K]

Answer:

The area of the triangle is A=\sqrt{\frac{4027}{2}}

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

A=\frac{1}{2}||{\bf u} \times {\bf v} ||

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

{\bf AB} and {\bf AC}

The vector {\bf AB} is the difference of point B minus point A

{\bf AB}=(5-3,5-5,0-9)=(2,0,-9)

and the vector {\bf AC} is the difference of point C minus point A

{\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)

Next we need to find the cross product of this vectors.

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

This is the definition of cross product of two vectors in space:

Let {\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k} and {\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k} be vectors in space. The cross product of {\bf u} and {\bf v} is the vector

{\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}

Applying this definition we get

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}

||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}

The area of the triangle is

A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}

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