HELP ME ASAP PLS.......

Mathematics

1 answer:

Sergio [31]3 years ago

3 0

Answer:

Step-by-step explanation: 32

You might be interested in

Friday night, a pizza parlor sold

SpyIntel [72]

The total is. Friday 573

6 0

3 years ago

___ cosb =1/2 sin(a+b)+sin(a-b)?

vodomira [7]

Answer:

That would be sina.

Step-by-step explanation:

sin(a+b) = sinacosb + cosasinb

sin(a-b) = sinacosb - cosasinb

Adding we get sin(a+b) + sin(a-b) = 2sinaccosb

so sinacosb = 1/2sin(a+b) + sin(a-b)

8 0

3 years ago

Read 2 more answers

Whoever gets this right gets brainlyess answer and it's worth 10 points :)

Lunna [17]

60% = 0.6
12 / 0.6 = 20

answer 12 is 60% of 20

8 0

3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.