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padilas [110]
2 years ago
6

Marcia has x number of homework problems. When she has done 10 of them, she is 1/4 finished. How many homework problems did she

have
Mathematics
1 answer:
professor190 [17]2 years ago
8 0

Answer:

so in 10 it is 1/4 so

here it's obvious if 10 in 1 then 40 in 4

so she have 40 problems

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For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = \sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }

3 0
3 years ago
Solve for x in the triangle. Round your answer to the nearest tenth.
natta225 [31]

Answer:

x = 5.5 to the nearest tenth.

Step-by-step explanation:

Here we have a right triangle with one angle (65 degrees) given.  Side x is the "side adjacent to the angle" and is to be found.  The hypotenuse is 13.

The cosine function makes use of these three knowns:  the angle, the hypotenuse and the adjacent side.  Thus:

cos 65 degrees = adj / hyp = x / 13, or

x = 13 cos 65

Evaluating this on a calculator, we get  x = 5.49, or x = 5.5 to the nearest tenth.

5 0
3 years ago
An architect wants an artistic flair to the house he is building, so he designs windows that are three fourths of a circle in sh
larisa86 [58]

The amount of rim needed for each window is 141.4 in

<h3>How to find the length of the outer rim?</h3>

Since the outer rim is the length of an arc, we use the formula for length of an arc of a circle.

<h3>What is an arc?</h3>

An arc is part of section of the circumference of a circle

<h3>What is the length of an arc?</h3>

So, length of arc, L = Ф/360 × 2πR where

  • Ф = central angle of arc and
  • R = radius of circle.

Gven that for the window rim

  • Ф = angle of the rim = 270° and
  • R = radius of the rim = 30 in

Substituting the values of the variables into the equation for L, we have

L = Ф/360 × 2πR

L = 270°/360° × 2π × 30 in

L = 3/4 × 2π × 30 in

L = 3/2 × π × 30 in

L = 3 × π × 15 in

L = 45π in

L = 141.37 in

L ≅ 141.4 in

So, the amount of rim needed for each window is 141.4 in

Learn more about length of an arc here:

brainly.com/question/8402454

#SPJ1

7 0
2 years ago
Help i need an answer please dont answer if you are not positive
spayn [35]
What is the area of the shaded region and the circle inside?

r=20,1m+13,2m=33,3m
A_1=\pi r^2
A_1=33,3^2\pi
A_1=1108,89\pi

What is the area of the circle inside?

A_2=20,1^2\pi
A_2=404,01\pi

What is the area of the shaded region?

1108,89\pi -404,01\pi =704,88\pi
704,88\pi \approx 704,88*3,14\approx 2213,3232\approx \underline{2213,32}

The answer: 2213,32 :)
5 0
3 years ago
kaitlin received a $70 gift card for a coffee store. she used it in buying some coffee that cost $7.69 per pound. after buying t
aksik [14]
Kaitlin bought 4 pounds of coffee.

70-39.24=30.76
30.76 ÷ 7.69= 4
8 0
2 years ago
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