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Shalnov [3]
3 years ago
11

Noah is buying a pair of jeans and using a coupon for 10% off. The total price is $56.70, which includes $2.70 in sales tax. Noa

h's purchase can be modeled by the equation:
x - 0.1x + 2.70 = $56.70
​
Mathematics
1 answer:
Kay [80]3 years ago
4 0
$56.70 take away the tax first which brings you to $54 then 54x.10% is 5.40 so take 5.40 away from $54 you then have $48.60 then you can add the tax back in +2.70 = $51.30
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A pair of snow boots at an equipment store in Big Bear that originally cost $80 is on sale for $56. What is the rate of discount
8_murik_8 [283]

Divide the sale price by the original price:

56 / 89 = 0.7

Multiply by 100:

0.7 x 100 = 70%

The sale price is 70% of the original price, so the discount would be 30% (100-70= 30)

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PLS HELP ME!! STATE THE DOMAIN AND RANGE OF EACH RELATION AND WHETHER ITS A FUNCTION​
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Represent each sum as a single rational number.<br> 7 + (1/9)
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Step-by-step explanation:

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3 years ago
Write the next three terms of the arithmetic sequence.<br> First term: 2<br> Common difference: 13
IRINA_888 [86]
15, 28, 41.

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4 0
3 years ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
2 years ago
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