Answer:
The correct answer is A electron on the aniline nitrogen are somehow delocalized to the aromatic ring.
Explanation:
The structure of aniline contain double bonds and lone pair of electron in the nitrogen atom of -NH2 group that is attached to the benzene ring.
The electron pair present in the nitrogen atom of -NH3 group of aniline undergo delocalization with the aromatic ring of benzene resulting in the formation of resonance hybrid that increases the ability of nitrogen atom of -NH2 group of aniline to easily donate that lone pair of electron.
ON the other hand the resonance stabilization cannot be possible with the cyclohexylamine ring as it is saturated.
Answer:
B. 17.0.
Explanation:
Hello!
In this case, considering that based on the atomic mass of the carbon atom, which means that 1 mole of carbon weights 12.01 grams, we can set up the following proportional factor to compute the moles of carbon in 200.0 grams:
Thus, the answer would be B. 17.0.
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<h3>
Answer:</h3>
2265 g Fe₃O₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O
[Given] 705.0 g H₂O
<u>Step 2: Identify Conversions</u>
[RxN] 4 mol H₂O → 1 mol Fe₃O₄
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Fe - 55.85 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol
<u>Step 3: Convert</u>
- Set up stoich:
- Multiply/Divide/Cancel units:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 4 sig figs.</em>
2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄
Explanation:
Sodium and potassium are in the same group on the periodic table because they both have similar number of valence electrons (1 electron) in their shells
Na = 2,8,1
K = 2,8,8,1