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2 years ago

Which of the following is a chemical property? A. Boiling point B. Electrical conductivity C. Flammability D. Malleability

Chemistry

1 answer:

Scrat [10]2 years ago

7 0

Answer:

I say its C flammability

Explanation:

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3 years ago

It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta

Zigmanuir [339]

Answer:

$\lambda=241.9\ nm$

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,

1 mole = $6.023\times 10^{23}\ electrons$

So,

$6.023\times 10^{23}$ electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of $\frac {495.0}{6.023\times 10^{23}}\ kJ$ of energy.

Energy required = $82.18\times 10^{-23}\ kJ$

Also,

1 kJ = 1000 J

So,

Energy required = $82.18\times 10^{-20}\ J$

Also, $E=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

So,

$79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}$

$\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}$

$\lambda=\frac{19.878}{10^6\times \:82.18}$

$\lambda=2.4188\times 10^{-7}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=241.9\ nm$

6 0

3 years ago

What were the limitations of Dobereiner's classifcation?

yawa3891 [41]

Answer:

Dobereiner could find only three triads; . i.e total of 9 elements only. However the total number of elements were more than that of those encompassed in Dobereiner's Triad

Explanation:

5 0

3 years ago

Read 2 more answers

A sample of gas has an initial volume of 15 L and an initial pressure of 4.5 atm. If the pressure changes to 1.8 atm, what is th

olga_2 [115]

Answer:

37.5 L

Explanation:

Initial Volume, V1 = 15L

Initial Pressure P1 = 4.5 atm

Final Pressure, P2 = 1.8 atm

Final Volume V2 = ?

The relationship between these variables is given as;

P1V1 = P2V2

V2 = PIV1 / P1

Inserting the values;

V2 = 4.5 * 15 / 1.8

V2 = 37.5 L

4 0

3 years ago

Read 2 more answers

How many moles of H2O will be produced from 26.0 g of H2022<br> Stoichiome

lukranit [14]

Answer:

0.7644 moles of H₂O

Explanation:

The balance chemical equation is as follow;

2 H₂O₂ → 2 H₂O + O₂

To solve this problem we will first calculate the moles of H₂O₂ as,

Moles = Mass / M/Mass

Moles = 26.0 g / 34.01 g/mol

Moles = 0.7644 mol

Secondly,

According to equation,

2 moles of H₂O₂ produces = 2 moles of H₂O

Hence,

0.7644 mol of H₂O₂ will produce = X moles of H₂O

Solving for X,

X = 2 mol × 0.7644 mol / 2 mol

X = 0.7644 moles of H₂O

5 0

3 years ago