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Stolb23 [73]
3 years ago
14

Round the following number to four figures: 45.4673

Chemistry
2 answers:
zhenek [66]3 years ago
7 0

This says four figures. The 4 figures you should use are 4546  with a peek at 7 to see what effect it will have on the 4 main figures.

45.467 rounds to 45.47

You round the 4th figure up one. You are not concerned about the decimal places in this question.

andre [41]3 years ago
4 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ You would need to round from the value in the thousandths column

As the number is 7, you would round up

45.47 <== this is the answer

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Sonbull [250]

Answer:

A hot air balloon taking off

Explanation:

4 0
3 years ago
V1 = l; P1=40Pa; P2= 100 kpa; V2= 1.0 L please help!
blsea [12.9K]

Answer:

V1 = 2500 L

Explanation:

V1P1 = V2P2

x * 40 = 100.000 * 1.0

==> x =2500 L

6 0
3 years ago
Before entering the cyclotron, the particles are accelerated by a potential difference V. Find the speed v with which the partic
vesna_86 [32]

Answer:

Speed, v=\sqrt{\dfrac{2qV}{m}}

Explanation:

The device which is used to accelerate charged particles to higher energies is called a cyclotron. It is based on the principle that the particle when placed in a magnetic field will possess a magnetic force. Just because of this Lorentz force it moves in a circular path.  

Let m, q and V are the mass, charge and potential difference at which the particle is accelerated.

The work done by the particles is equal to the kinetic energy stored in it such that,

qV=\dfrac{1}{2}mv^2

v is the speed with which the particles enter the cyclotron

So,

v=\sqrt{\dfrac{2qV}{m}}

So, the speed with which the particles enter the cyclotron is v=\sqrt{\dfrac{2qV}{m}}. Hence, this is the required solution.

7 0
3 years ago
What compound are formed with lithium and selenium?
love history [14]

Answer:

Lithium selenide Lithium selenide (Li2Se) 12136-60-6 Dilithium selenide lithium selenidolithium

Molecular Weight 92.9 g/mol

Dates Modify 2020-11-15 Create 2005-08-08

5 0
3 years ago
Read 2 more answers
Study this chemical reaction: (aq)(s)(s)(aq) Then, write balanced half-reactions describing the oxidation and reduction that hap
disa [49]

The question is incomplete, complete question is:

Study this chemical reaction:

FeSO_4 (aq) + Zn (s)\rightarrow Fe (s) + ZnSO_4 (aq)

Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

Oxidation:

Reduction:

Answer:

Oxidation taking place in given reaction :

Zn(s)\rightarrow Zn^{2+}+2e^-

Reduction taking place in given reaction;

Fe^{2+}(aq)+2e^-\rightarrow Fe(s)

Explanation:

Redox reaction is defined as the reaction in which oxidation and reduction reaction occur side by side.

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

FeSO_4 (aq) + Zn (s) \rightarrow Fe (s) + ZnSO_4 (aq)

In the given reaction, iron(II) ions are getting reduced and zinc metal is getting oxidized to zinc(II) ions.

Oxidation :

Zn(s)\rightarrow Zn^{2+}+2e^-

Reduction ;

Fe^{2+}(aq)+2e^-\rightarrow Fe(s)

6 0
3 years ago
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