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nataly862011 [7]
3 years ago
15

Worked a total of

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

26 for the first and 18 for the second.

Step-by-step explanation: 44-8=36. 36÷ 2=18. 18+8=26. So, you get 26 and 18 hours.

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PLEASE HELP ILL GIVE BRAINLIEST
Art [367]

Answer: 10

Step-by-step explanation:

count the dots from number 2 and below

6 0
2 years ago
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Round 832 to the nearest hundreds place.
elena-s [515]

Answer:

800

Step-by-step explanation:

Look at the tens if it's 0-4 keep the number the same if 5-9 go up one number

6 0
3 years ago
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The equation $y=-4.9t^2+3.5t+5$ describes the height (in meters) of a ball thrown upward at $3.5$ meters per second from $5$ met
Georgia [21]

Answer:

Step-by-step explanation:

The position function is

s(t)=-4.9t^2+3.5t+5 and if we are looking for the time t it takes for the ball to hit the ground, we are looking for the height of the ball when it is on the ground. Of course the height of anything on the ground is 0, so if we set s(t) = 0 and solve for t, we will find our answer.

0=-4.9t^2+3.5t+5 and factor that however you are currently factoring in class to get that

t = -.71428 seconds or

t = 1.42857 seconds (neither one of those is rational so they can't be expressed as fractions).

We all know that time will never be a negative value, so the time it takes this ball to hit the ground is

1.42857 seconds (round how you need to).

4 0
3 years ago
Write your own explicit formula. List the first 4 terms and solve for the 10th term using the formula. (show your work)
Shalnov [3]

Answer:

See below.

Step-by-step explanation:

Formula:

a_n = 3(n + 4)

First term: n = 1

a_1 = 3(1 + 4) = 15

Second term: n = 2

a_2 = 3(2 + 4) = 18

Third term: n = 3

a_3 = 3(3 + 4) = 21

Fourth term: n = 4

a_4 = 3(4 + 4) = 24

Tenth term: n = 10

a_{10} = 3(10 + 4) = 42

4 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
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