All categories

4 years ago

4x + 8 = 2x + 7 + 2x - 20. PLEASE SHOW WORK!!!

Mathematics

2 answers:

garik1379 [7]4 years ago

6 0

How to get answer:

$\mathrm{Group\:like\:terms}\\4x+8=2x+2x+7-20\\\mathrm{Add\:similar\:elements:}\:2x+2x=4x\\4x+8=4x+7-20\\\mathrm{Add/Subtract\:the\:numbers:}\:7-20=-13\\4x+8=4x-13\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}\\4x+8-8=4x-13-8\\\mathrm{Simplify}\\4x=4x-21\\\mathrm{Subtract\:}4x\mathrm{\:from\:both\:sides}\\4x-4x=4x-21-4x\\Simplify\\0=-21\\The\:sides\:are\:not\:equal\\$

maksim [4K]4 years ago

5 0

Steps:

4x + 8 = 2x + 7 + 2x - 20

Group like terms:

4x + 8 = 2x + 2x + 7 - 20

Add similar elements: 2x + 2x = 4x

4x + 8 =4x + 7 - 20

Add/Subtract the numbers: 7 - 20 = -13

4x + 8 = 4x - 13

Subtract 8 from both sides

4x + 8 - 8 = 4x - 13 - 8

Simplify:

4x = 4x - 21

Subtract 4x from both sides:

4x - 4x = 4x - 21 - 4x

Simplify

0 = -21

Hope this helps! :) and Happy Halloween! ~Zane

You might be interested in

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

3 years ago

Please answer with proof/work I give points

Phoenix [80]

Answer:

H. 8.874 hours

Step-by-step explanation:

There is a seven, that has the value of 7/100. 7/100 as a decimal is .07 because there is a 7 in the hundredths place. There has to be a number that contains 7/100, or a value in the hundredths place, and that is 8.874.

Hope this helps!

3 0

3 years ago

Read 2 more answers

Multiply 4/5 by the reciprocal of −2/10.

Svetach [21]

Answer:

4/5*reciprocal of -2/10

The reciprocal of -2/10 is 10/-2

4/5*10/2

Cancelling the numbers

-4 is the answer