Need Help!!Graph the first 6 terms of a sequence where a1 = −3 and d = 4.
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The translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.
In the question, we are asked to translate the given figure 2 units left and 7 units down.
In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.
For any point P(x, y) the given rule says that after translation,
P(x, y) becomes P'(x - 2, y - 7).
The coordinates of the given figure are:
A(3,9), B(5,9), C(5,2), and D(1,4).
After translation, these points can be shown as:
A(3,9) becomes A'(1,2).
B(5,9) becomes B'(3,2).
C(5,2) becomes C'(3,-5).
D(1,4) becomes D'(-1,-3).
Thus, the translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.
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