Question

Graph the image of T(

Answer 1

Answer:

$T' = (-7,10)$

Step-by-step explanation:

Given

$T = (10,7)$

$r = 270^o$ counterclockwise

Required

Graph of T'

The rule to this is:

$(x,y) \to (-y,x)$

So, we have:

$T(10,7) \to T' (-7,10)$

Hence:

$T' = (-7,10)$

See attachment for graph