Raul crosses Main Street when he walks home from school. The graph of the function d(t)=4|t-0.75) shows Raul's distance, in mile
s, from Main Street after thours. The domain of the function is 0 <= x <= 1.5 The graph shows his entire trip
1 answer:
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<u>Additional requirements in figure</u> :-
Mark point :-
- A
- B
- C
- D
- E
Draw a straight line from E to AB .
And the point line joins mark it as "F" .
It will generate quadrilateral FBCD.
we get to know In quadrilateral left angle is 90°
How ?
{
proof :
As three angles are given 90° So third angle will also be 90°
Reason:
→ Sum of interior angles = 2 (no. of angles - 2 × 180°
→Sum of interior angles = (4-2 × 180°)
→Sum of interior angles = (2 × 180°)
→Sum of interior angles = 360°
}
<u>✿</u><u>Now let the left angle be </u><u>x</u>
- 90° +90° + 90° + x = 360°
- 180° + 90° + x = 360°
- 270° + x = 360
- x = 360° - 270°
- x = 90°
<u>we know</u> :
Area of rectangle = Length × Breadth
STEPS :
- Area of rectangle = Length × Breadth
- Area of rectangle = 7 × 8
- Area of rectangle = 56 in²
<u>Now let's find EF</u> :
- EF = BD - EC
- EF = 7 - 4
- EF = 3 in
<u>To find A</u>
<u>F</u> :
- A•F = AB - CD
- A•F = 12 - 8
- A•F = 4 in
<u>In triangle AFE</u>:
- EF is base of triangle
- A•F is height of triangle
We know :
<u>Area of triangle =(</u><u> </u><u>Height</u><u> </u><u>×</u><u> </u><u>Base)/2</u>
Steps :
- Area of triangle = (Height × Base)/2
- Area of triangle = (4 × 3)/2
- Area of triangle = 12/2
- Area of triangle = 6 in²
<u>To find area of figure</u> :
- Area of figure = Area of rectangle + Area of triangle
- Area of figure = 56 + 6
- Area of figure = 62 in²
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