Answer:
Step-by-step explanation: 50r - 6= 82r-70
Add 50r to 82r which equals to 132 r
Now add the the 70 to the left side so -6+70 should equal 76.
Now it should look like this 76=132r
To get the value of r you have to divide 76/132 on both sides of the equation and your answer should be 0.57=r
Answer:
y=0.8x
Step-by-step explanation:
take two points from the graph
(5,4) and (0,0)
then do y2-y1/x2-x1
4-0/5-0
4/5=.8
Answer:
D. A rectangle and an isosceles triangle
Step-by-step explanation:
In the figure attached, the sign is shown. There we can see an arrow, which can be decomposed into a rectangle (on the left of the figure) and an isosceles triangle (on the right of the figure)
Answer:
a. 12 feet b. 12 feet 0.5 inches c. 8.33 %
Step-by-step explanation:
a. How far out horizontally on the ground will it protrude from the building?
Since the rise to run ratio is 1:12 and the building is 12 inches off the ground, let x be the horizontal distance the ramp protrudes.
So, by ratios rise/run = 1/12 = 12/x
1/12 = 12/x
x = 12 × 12
x = 144 inches
Since 12 inches = 1 foot, 144 inches = 144 × 1 inch = 144 × 1 foot/12 inches = 12 feet
b. How long should the ramp be?
The length of the ramp, L is gotten from Pythagoras' theorem since the ramp is a right-angled triangle with sides 12 inches and 144 inches respectively.
So, L = √(12² + 144²)
= √[12² + (12² × 12²)]
= 12√(1 + 144)
= 12√145
= 12 × 12.042
= 144.5 inches
Since 12 inches = 1 foot, 144.5 inches = 144 × 1 inch + 0.5 inches = 144 × 1 foot/12 inches + 0.5 inches = 12 feet 0.5 inches
c. What percent grade is the ramp?
The percentage grade of the ramp = rise/run × 100 %
= 12 inches/144 inches × 100 %
= 1/12 × 100 %
= 0.0833 × 100 %
= 8.33 %
Hey there!
Assuming #1 ….
x + 7x + x = 180°
REWORD
1x + 7x + 1x = 180°
COMBINE the LIKE TERMS
(1x + 7x + 1x) = 180°
8x + 1x = 180°
9x = 180°
DIVIDE 9 to BOTH SIDES
9x/9 = 180/9
CANCEL out: 9/9 because it equal 1
KEEP: 180/9 because it give you the x-value
NEW EQUATION: x = 180/9
SIMPLIFY IT!
x = 20
||||~~||||~~||||~~||||~~~||||~~||||~~||||~~||||~~~||||
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)