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3 years ago

7

Harrison goes to a thrift shop and is going to buy a sports coat, a dress shirt, or a tie. Harrison tends to like everything but

decides to stick to a power tie, which would be a tie with red or yellow in it. The thrift shop has 6 sports coats that fit him and 8 dress shirts that fit him. The thrift shop has 4 red ties and 5 yellow ties. How many choices does Harrison have

1 answer:

Sphinxa [80]3 years ago

3 0

Answer:

Harrison has 432 choices.

Step-by-step explanation:

Harrison will choose:

One sports coat from a set of 6.

One dress shirt from a set of 8.

One power tie from a set of 4 + 5 = 9.

How many choices does Harrison have?

6*8*9 = 432

Harrison has 432 choices.

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Elza [17]

Answer:

(a) The slope of f(x) is greater than the slope of g(x)

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Step-by-step explanation:

Given

$\begin{array}{cc}x & {f(x)} & -1&-9&0&-1&1&7 \ \end{array}$

$g(x) = 3x - 2$

Solving (a): Compare the slopes

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This gives:

$m = \frac{f(0) - f(1)}{0 - 1}$

$m = \frac{f(0) - f(1)}{- 1}$

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$m = \frac{-1 - 7}{- 1}$

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The slope of g(x) can be gotten using the following comparison

$g(x) = mx + b$

$m \to slope$

So:

$g(x) = 3x -2$

$m = 3$

$m_{f(x)} > m_{g(x)}$

Solving (b): Compare the y intercept

y intercept is when $x = 0$

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$f(0) = -1$

From the equation of g(x)

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<em></em> $f(0) > g(0)$ <em></em>

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3 years ago

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Firlakuza [10]

This seems like a right triangle problem.

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So, the equation is $4^{2} +x^{2} =14^{2}$ .

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x^{2}= 196-16

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3 years ago

Read 2 more answers

I forgot to send this in my last question, Sorry!

pshichka [43]

$1. \: = > 4( - 7) \\ = 4 \times - 7 \\ = - 28$

$3. \: = > 9( - 12) \\ = 9 \times - 12 \\ = - 108$

$4. \: = > - 6( - 8.75) \\ = 6 \times 8.75 \\ = 52.5$

$5. = > 27( - 3) \\ = 27 \times - 3 \\ = - 81$

$7. \: = > - 55(0) \\ - 55 \times 0 \\ = 0$

$8. \: = > ( - 7)( - 7.25) \\ = 7 \times 7.25 \\ = 50.75$

$11. \: = > ( - 1) {}^{4} \\ = 1 {}^{4} \\ = 1$

$13. = > 42 \div ( - 7) \\ = - (42 \div 7) \\ = - 6$

$15. = > - 9 \div 3 \\ = - (9 \div 3) \\ = - 3$

<h2>Solved ✔︎</h2>

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2 years ago

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Step2247 [10]

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-------------------------------\\\\
0=\sqrt[3]{x}\implies \boxed{0=x}$

now, f(0) = 0, and f(-8) is an imaginary value or no real value.

now, f(-10) will also give us an imaginary value

and f(1) = 4

so, doing a first-derivative test on 0, is imaginary to the left and positive on the right, and before and after 1, is positive as well, so f(x) is going up on those intervals.

however, f(0) is 0 and f(1) is higher up, so the absolute maximum will have to be f(1), and we can use f(0) as a minimum, and since it's the only one, the absolute minimum.

the other two, the endpoint of -10 and the critical point of -8, do not yield any values for f(x).

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3 years ago