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In-s [12.5K]
3 years ago
8

A random sample of 64 freshmen spent an average of 14 hours per week watching television. the sample standard deviation was 32 h

ours per week. what is the critical value for a 95% confidence interval for the population mean?
Mathematics
1 answer:
NemiM [27]3 years ago
3 0

Answer:

+/- 1.9983

Step-by-step explanation:

The critical values for a confidence interval for the population mean, with population standard deviation not known, are obtained from the student's t distribution.

The sample size is given as 64. The degrees of freedom will thus be;

sample size - 1 = 64 - 1 = 63

The confidence level is given as 95%. The level of significance will thus be;

100 - 95 = 5%.

The area in the right-tail will thus be 2.5%. Therefore, we looking for a t-value such that the area to its right is 2.5% and the degrees of freedom being 63. From the t-tables we have;

+/- 1.9983

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(a)

The formula to compute the probability of an event <em>E</em> is:

P(E)=\frac{Favorable\ no.\ of\ frequencies}{Total\ NO.\ of\ frequencies}

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Compute the probabilities for the rest of the values of <em>X</em> in the similar way.

The probabilities are shown in the table.

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