Answer:
Step-by-step explanation:
18in^2(3mi/in)^2
18in^2(9mi^2/in^2)
162 mi^2
Answer:
-
- Dimensions of the flag:
- Area of the flag:
Step-by-step explanation:
<em><u>The missing figure of the exercise is attached.</u></em>
<em><u /></em>
We know that the perimeter of the triangle is given by:
Where "s" is the side lenght of the triangle.
Solving for "s", we get:
Therefore, if the perimeter of the triangle is 126 inches, its side length is:
Since 
, we know that "s" in feet is:
The area of a rectangle can be calculated with this formula:
Where "l" is the lenght and "w" is the width
We can observe in the figure that the lenght and the width of the flag are:
Then, the dimensions of the flag are:
And the area is:
Answer:
Step-by-step explanation:
72 + 4t > 400
X could = 83 (since 82 will give you 400) or higher
<span> sin20 * sin40 * sin60 * sin80
since sin 60 = </span><span> √3/2
</span>√3/<span>2 (sin 20 * sin 40 * sin 80)
</span>√3/<span>2 (sin 20) [sin 40 * sin 80]
</span>
Using identity: <span>sin A sin B = (1/2) [ cos(A - B) - cos(A + B) ]
</span>√3/<span>2 (sin 20) (1 / 2) [cos 40 - cos 120]
</span>√3/4<span> (sin 20) [cos 40 + cos 60]
</span>
Since cos 60 = 1/2:
√3/4<span> (sin 20) [cos 40 + (1/2)]
</span>√3/4 (sin 20)(cos 40) + √3/8<span> (sin 20)
</span>
Using identity: <span> sin A cos B = 1/2 [ sin(A + B) + sin(A - B) ]
</span>√<span>3/4 (1 / 2) [sin 60 + sin (-20)] + </span>√3/8<span> (sin 20)
</span>
Since sin 60 = √3/<span>2
</span>√3/8 [√3/2 - sin 20] + √3/8 (sin 20)
3/16 - √3/8 sin 20 + √3/8<span> sin 20
</span>
Cancelling out the 2 terms:
3/16
Therefore, sin20 * sin40 * sin60 * <span>sin80 = 3/16</span>
Answer:
123
Step-by-step explanation:
123
123
