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dimaraw [331]
3 years ago
10

A candle burned at a steady rate. After 34 minutes, the candle was 11.2 inches tall. Eighteen minutes later, it as 10.75 inches

tall. Use and equation in point-slope form to determine the height of the candle after 2 hours. Round the answer to the tenth place if necessary.
After 2 hours, the candle will be how many inches tall?
Mathematics
1 answer:
stepladder [879]3 years ago
4 0
X = time, minutes
y = length, inches

When x = 32 min, y = 11.2 in
When x = 32+18 = 50, y = 10.75 in
Assume that a linear relatioship exists between x and y.

In table form, the given data is
x, min:   32       50
y, in:     11.2   10.75

The slope is
m = (10.75 - 11.2)/(50 - 32) = -0.025

In point-slope form, the required equation is


When x = 3 hours = 180 minutes, obtain
y - 10.75 = -0.025*(180 - 50) = -3.25
y = -3.25 + 10.75 = 7.5 in

Answer: 7.5 inches

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Reflect triangle stu across line st which of these is a valid reason why the image u will coincide with j
hjlf

Answer:

4. None of the above

Step-by-step explanation:

Reflection is a type of transformation that can be used to change the orientation of a given figure or shape without changing it size and shape.

When triangle STU is reflected across ST, the image U coincides with J because the two are on the opposite side and at the same distance from ST. Therefore, J is like the image of U.

7 0
3 years ago
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
Determine if the following relation represents a function or not.
artcher [175]

Answer:

It is a function.

Step-by-step explanation:

Functions are relations in which one domain value is assigned to exactly one range value. The x-value must not repeat in the relation set for it to be a function.

{(2,3), (4,3), (6,3), (5,9), (3,9)}

There are no repeating x-values given.

The relation should be a function.

Hope this helps.

6 0
3 years ago
The equation of the graphed line in point-slope form is A , and its equation in slope-intercept form is B .
mojhsa [17]
The correct letter is B I think
5 0
3 years ago
What is the area of the composite figure?
german

Answer:

16 + 6pi cm

Step-by-step explanation:

We have a square of length 4 cm

A = s^2 = 4^2 = 16

We have 3 semi circles

with radius 2

A semi circle has an area of

1/2 pi r^2 = 1/2 pi (2)^2 = 1/2 (4pi) = 2pi

There are 3 of them

3 * 2 pi = 6pi

Add the areas together for the square and the semicircles

16 + 6pi

6 0
3 years ago
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