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2 years ago

There are 2.54 centimeters in 1 inch. There are 100 centimeters in 1 meter. How many inches are there in 12 meters

Mathematics

1 answer:

lesya692 [45]2 years ago

7 0

Answer:

1200 centimeters

Step-by-step explanation:

if you have 100 centimeters in 1 meter and there are 12 meters you can just multiply the number of centimeters by 12 or whatever number is needed in this case 12 so when you multiply 12 x 100 you get 1200

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Explain how you know that x^2-8x+20 is always positive. <br> Please help.

IRISSAK [1]

Answer:

if you rearrange to complete the square, you get (x^2-4)^2 +4

and seeing as anything squared will always be positive or zero, the lowest possible value for (x^2-4)^2 is 0, when x = 4

and 0 + 4 = 4, which is greater than 0, so positive

Step-by-step explanation:

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3 years ago

The job Andrew has this summer paid 7.25 an hour and the job he had last Summer paid 6.50 an hour. how much more does Andrew ear

vladimir2022 [97]

Answer:

30 Dollars more

Step-by-step explanation:

This summer he earned = 7.25 X 40 = 290

Last summer he earned = 6.5 X 40 = 260

How much more he earned in 40 hours = 290-260= 30 dollars more

Answer from Gauthmath

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2 years ago

What is the probability of 15 people having the same birthday

Paladinen [302]

Answer:

1 out of 15

Step-by-step explanation:

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3 years ago

En una fábrica se empaquetan paletas en cajas, en cada caja caben

almond37 [142]

Answer:

205,968

Step-by-step explanation:

Si hay 3678 palets por caja, entonces multiplicamos 3678 por 56. 3678 por 56= 205.968. Por cierto, eres la primera persona a la que ayudé en español.

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3 years ago

Two perpendicular lines have opposite y-intercepts. The equation of one of these lines is

xeze [42]

Answer: The required x-co-ordinate of the point of intersection of two lines is $-\dfrac{2bm}{m^2+1}.$

Step-by-step explanation: Given that two perpendicular lines have opposite y-intercept and the equation of one of the lines is

$y=mx+b.$

We are to express the x-coordinate of the intersection point of the lines in terms of m and b.

Let the slope and y-intercept of the other line be s and c respectively.

Since the product of the slopes of two perpendicular lines is -1 and -b is the opposite of b, so we have

$ms=-1~~~\Rightarrow s=-\dfrac{1}{m}$

and c = -b.

That is, the equation of the other line is

$y=sx+c\\\\\Rightarrow y=-\dfrac{1}{m}-b.$

Comparing the equations of both the lines, we get

$mx+b=-\dfrac{1}{m}x-b\\\\\\\Rightarrow mx+\dfrac{1}{m}x=-2b\\\\\\\Rightarrow \dfrac{m^2+1}{m}x=-2b\\\\\\\Rightarrow x=-\dfrac{2bm}{m^2+1}.$

Thus, the required x-co-ordinate of the point of intersection of two lines is $-\dfrac{2bm}{m^2+1}.$

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3 years ago