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denpristay [2]
3 years ago
13

There are 2.54 centimeters in 1 inch. There are 100 centimeters in 1 meter. How many inches are there in 12 meters

Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

1200 centimeters

Step-by-step explanation:

if you have 100 centimeters in 1 meter and there are 12 meters you can just multiply the number of centimeters by 12 or whatever number is needed in this case 12 so when you multiply 12 x 100 you get 1200

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You and some friends have $30. You want to order large pizzas (p) that are $9 each and drinks
DochEvi [55]
Given:
Budget = $30
cost of pizza = $9
cost of drinks = $1
number of pizza = p
number of drinks = d

pizza and drinks should only be equal to or less than the budget of $30.

$9p + $1d <u>< </u>$30

unit cost of pizza :          9 
unit cost of drinks :         1
total cost of set (p & d) 10

pizza = 9/10 x 30 = 27 total cost of pizza
drinks =1/10 x 30 =   3 total cost of drinks

27 ÷ 9 = 3 number of pizzas to order 
  3 ÷ 1 = 3 number of drinks to order

To check:

9p + 1d <u>< </u>30
9(3) + 1(3) <u>< </u>30
27 + 3 <u>< </u>30
30 <u>< </u>30
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Write and solve a real world word problem in which there are three tables for every 8 chairs
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3 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

5 = 1.96*\frac{22}{\sqrt{n}}

5\sqrt{n} = 43.12

\sqrt{n} = \frac{43.12}{5}

\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

n = 74.4

We need a sample size of at least 75.

6 0
3 years ago
Read 2 more answers
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