Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
Answer:
7
Step-by-step explanation:
Substitute x = -4 :
f(-4) = 3 - (-4)
= 3 + 4
= 7
6.11
see- .8 .9 .10 so its .11
Answer:
7
Step-by-step explanation:
31 Wings (already cooked)
+ 32 Wings (started cooking)
= 63 Wings total
divided by 9 customers
= 7 per person
Answer:
well i like corn
Step-by-step explanation:
