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2 years ago

Rose is 60 inches tall. how many feet tall is Rose

Mathematics

1 answer:

nata0808 [166]2 years ago

4 0

Answer:

5 feet

Step-by-step explanation: 60 divided by 12 inches is 5 feet

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Given that PS is a median of triangle PQR, find RQ A.6 B.12 C.19 D.38

Zinaida [17]

The median triangle is a line segment that connects the vertex and the midpoint of the opposite side. Therefore, in the given, we can say that RS = QS

Equating RS and QS, we will find the value of X

RS = QS
5x-11 = 2x+7
5x-2x = 7+11 ⇒ combine like terms
3x = 18 ⇒ divide both sides by 3 to get the x value
x = 6

Find the value of RS and QS, in this, we will show that two are equal

5(6)-11 = 2(6)+7
19 = 19 ⇒ correct

Therefore RQ is the sum of RS and QS or simply twice the length of either segment

RQ = 19 x 2 = 19 + 19 = 38 (D)

5 0

2 years ago

I need help writing a function rule for this set of values. Thanks!

Nonamiya [84]

Answer:

2-1/-2--4= 1/2

0-1/0-2=-1/-2

2-0/-1-0=2/-1

-2--1/4-2=-1/2

can i have a Brainliest plz thank you

3 0

2 years ago

Monique is planning the locations for three exhibit areas at the festival. She drew a model of one of the exhibit areas as shown

WITCHER [35]

The second area was translated 1 unit right and 6 units down to form the third exhibit area.

<h3>Transformation</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, dilation and rotation.

Translation is the movement of a point either up, down, left or right.

Given the translation (x,y)→(x+1,y+6). Hence:

The second area was translated 1 unit right and 6 units down to form the third exhibit area.

Find out more on Transformation at: brainly.com/question/1462871

7 0

2 years ago

In triangle ABC, c = 8, b = 6, and ∠C = 60°. sin∠B = _____

guajiro [1.7K]

Answer:
sin B = 0.65

Explanation:
To solve this question, we will need to use the sine law that is shown in the attached image.

Here, we have:
c = 8
b = 6
angle C = 60°

Therefore:
 $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$

$\frac{6}{sin(B)}$ = $\frac{8}{sin(60)}$

sin B = 0.649 which is approximately 0.65

Hope this helps :)

4 0

3 years ago

Read 2 more answers

Compute the matrix of partial derivatives of the following functions.

s344n2d4d5 [400]

For a vector-valued function

$\mathbf f(\mathbf x)=\mathbf f(x_1,x_2,\ldots,x_n)=(f_1(x_1,x_2,\ldots,x_n),\ldots,f_m(x_1,x_2,\ldots,x_n))$

the matrix of partial derivatives (a.k.a. the Jacobian) is the $m\times n$ matrix in which the $(i,j)$ -th entry is the derivative of $f_i$ with respect to $x_j$ :

$D\mathbf f(\mathbf x)=\begin{bmatrix}\dfrac{\partial f_1}{\partial x_1}&\dfrac{\partial f_1}{\partial x_2}&\cdots&\dfrac{\partial f_1}{\partial x_n}\\\dfrac{\partial f_2}{\partial x_1}&\dfrac{\partial f_2}{\partial x_2}&\cdots&\dfrac{\partial f_2}{\partial x_n}\\\vdots&\vdots&\ddots&\vdots\\\dfrac{\partial f_m}{\partial x_1}&\dfrac{\partial f_m}{\partial x_2}&\cdots&\dfrac{\partial f_n}{\partial x_n}\end{bmatrix}$

So we have

(a)

$D f(x,y)=\begin{bmatrix}\dfrac{\partial(e^x)}{\partial x}&\dfrac{\partial(e^x)}{\partial y}\\\dfrac{\partial(\sin(xy))}{\partial x}&\dfrac{\partial(\sin(xy))}{\partial y}\end{bmatrix}=\begin{bmatrix}e^x&0\\y\cos(xy)&x\cos(xy)\end{bmatrix}$

(b)

$D f(x,y,z)=\begin{bmatrix}\dfrac{\partial(x-y)}{\partial x}&\dfrac{\partial(x-y)}{\partial y}&\dfrac{\partial(x-y)}{\partial z}\\\dfrac{\partial(y+z)}{\partial x}&\dfrac{\partial(y+z)}{\partial y}&\dfrac{\partial(y+z)}{\partial z}\end{bmatrix}=\begin{bmatrix}1&-1&0\\0&1&1\end{bmatrix}$

(c)

$Df(x,y)=\begin{bmatrix}y&x\\1&-1\\y&x\end{bmatrix}$

(d)

$Df(x,y,z)=\begin{bmatrix}1&0&1\\0&1&0\\1&-1&0\end{bmatrix}$

5 0

3 years ago