<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
8x^2 - 4x
Step-by-step explanation:
add like terms
Help help help help help help
Step-by-step explanation:
By Law of Indices, a^m / a^n = a^(m-n).
Therefore a² / a⁸ = a^(-6).
x = -6.
The answer is D
Type 1 Type 2 plants have somewhat similar height distributions
