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NeX [460]
3 years ago
15

Which ratios are less than 8 to 10? Check all that apply. 6/20 3:5 50/100 13:15

Mathematics
1 answer:
poizon [28]3 years ago
6 0

9514 1404 393

Answer:

  6/20, 3:5, 50/100 are all less than 8/10

Step-by-step explanation:

It can help to give all the ratios a common denominator. (We'll use 100, and fudge the last one a bit.)

  8/10 = 80/100 . . . . our reference value

__

  6/20 = 30/100 . . . less than 8/10

  3/5 = 60/100 . . . . less than 8/10

  50/100 . . . . . . . . . less than 8/10

  13/15 ≈ 86.7/100 . . . more than 8/10

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The function f(x) = -(x-3)2 + 9 can be used to represent the area of a rectangle with a perimeter of 12 units, as a function of
pashok25 [27]

Answer:

Maximum area = 9 sq units

Step-by-step explanation:

f(x)=-(x-3)^2+9

which represents the area . As it is a quadratic equation it represents the parabola . And the vertex of the parabola will maximum area of for some value of x

let f(x) = y

y=-(x-3)^2+9

(x-3)^2=-(y-9)

Comparing it with the standard equation of parabola

y=(x-h)^2+k

we get h=3 and y=9

where (h,k) is the vertex (3,9)

Hence the maximum area of the rectangle will be 9

6 0
3 years ago
At a distance of 10 cm from a presumably isotropic, radioactive source, a pair of students measure 55 cps (cps = counts per seco
professor190 [17]

With an isotropic source, you can think on the radiation like a expanding sphere, where you will measure the same cps in any point while you keep the same distance to the source, ence the radius of the sphere remains constant. So, you know that the relation depends on the radius, also, when the sphere grows, the radiation in it expands in more surface, ence the density of particles will decrease, particularly, like \frac{1}{r^{2} }

then, in 15cm you will have 55cps = A/(10*10) where A is the "intensity of the source" whit this you can know the value of A = 55cps*100cm^{2}.

then, for 22cm, Y = 55cps*100/(22*22) = 20.66 cps.

7 0
4 years ago
Multiple Choice, could somebody help me with this?
ololo11 [35]

Answer:

option 5 and option 6

Step-by-step explanation:

option 5.

dilate with a scale factor of 1/2.

This is because we have to take as a reference the base circumference of the point p as the problem says, so we see the radius of that circumference is twice that of the other, so to get there it must be multiplied by 1/2

option 6.

reflect in the y-axis.

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3 0
4 years ago
The standard unit for measuring mass is the
a_sh-v [17]
Answer: Kilograms is the SI for mass
6 0
3 years ago
The lines given by the equations y=2x and y=4x+1 are
BartSMP [9]

the equations are already in slope-intercept form, therefore


\bf \begin{array}{|c|ll}
\cline{1-1}
slope-intercept~form\\
\cline{1-1}
\\
y=\stackrel{\stackrel{slope}{\downarrow }}{m}x+\stackrel{\stackrel{y-intercept}{\downarrow }}{b}\\\\
y=mx+b
\\\\
\cline{1-1}
\end{array}~\hspace{8em}y=\stackrel{slope}{2}x\qquad y=\stackrel{slope}{4}x+1


so their slopes are 2 and 4.

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8 0
4 years ago
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