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uranmaximum [27]
3 years ago
9

Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co

s4 (2x) dx 6. Z sin3 x dx 7. Z sec4 x tan3 x dx 8. Z tan5 x sec x dx
Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

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G+5>12 solution please i don’t know how to do this
Musya8 [376]

Answer:  g > 7

Graph has an open circle at 7 on the number line, shading to the right

================================================

Explanation:

Think of it like saying "I have a number, and I add on 5. The result is something larger than 12". You can guess and check your way to the answer, but the quickest way is to subtract 5 from both sides.

We subtract to undo the addition happening to the 'g'.

g+5 > 12

g+5-5 > 12-5

g > 7

So the number is larger than 7. For instance, if g = 8, then,

g+5 > 12

8+5 > 12

13 > 12

This is a true statement.

-------------------------

If you need to graph the solution, then you'll have an open circle at 7 on the number line. The open circle says to the reader "don't include this value as part of the solution set". Shade to the right of the open circle to describe all values larger than 7.

In summary, the graph has an open circle at 7 and shading to the right.

3 0
3 years ago
Which of the following expressions represents the solution to the inequality statement?
Alja [10]
Answer is <span>x ≥ 7

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3 0
3 years ago
Find the volume of the oblique cone shown round to the nearest tenth
xeze [42]

Answer:

The volume of cone is 707.9in³

Step-by-step explanation:

volume of cone = (1/3)πr²h

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h =16inches

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2(2w - 6) + 2(w) = 3(w + 8)
borishaifa [10]

Answer:

w=12

Step-by-step explanation:

4w-12+2w-3w-24=0

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3 years ago
1/5 ÷ 2. simple for a couple of points lol
Sergio039 [100]

0.1

Have a amazing day!!

8 0
3 years ago
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