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zubka84 [21]
3 years ago
14

Simplify (sin theta - cos theta) - (sin theta + cos theta)^2

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

\bf \begin{array}{llll} [sin(\theta )-cos(\theta )] &-& [sin(\theta )+cos(\theta )]^2\\\\ &&sin^2(\theta )+2sin(\theta )cos(\theta )+cos^2(\theta )\\\\ &&sin^2(\theta )+cos^2(\theta )+2sin(\theta )cos(\theta )\\\\ &&1+2cos(\theta )sin(\theta )\\\\ &&1+sin(2\theta ) \end{array} \\\\\\ sin(\theta )-cos(\theta )-[1+sin(2\theta )]\implies sin(\theta )-cos(\theta )-1-sin(2\theta )


I don't see it simplifying further.

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4. The stock market goes up more often that it goes down. Assume the probability that the stock market goes up in a randomly sel
tekilochka [14]

Answer:

a: 0.0022

b: 0.00002

c: 0.0002

d: 924

e:  0.0025

f: 0.6652

g:  Expected value 7.8 months, standard deviation 1.77 months

Step-by-step explanation:

This is a binomial situation.  Either the market goes up, or it doesn't.  (It could stay the same, but it doesn't offer that as an option, so we don't include it).

When calculating probability of a binomial situation, use the formula

(nCr)(p^r)(q^(n-r))   where p is the probability of success, q is the probabilty of failure, n is the the number of times the situation occurs, and r is the desired number of successful outcomes.  The function nCr tells us how many ways you can choose r items from n total items.  In this case, we are choosing some number of months, r, from 12 months, n

For our situation we have:  n = 12, r = 12, p = 0.6, q = 0.4,

For a:   (12C12)(0.6^12)(0.4^0) = (1)(0.0022)(1) = 0.0022

We want all 12 months of success and no months of failure

For b:   (12C0)(0.6^0)(0.4^12) = (1)(1)(0.00002) = 0.00002

We want all months of failure, and no months of success

For c:   (0.6^6)(0.4^6) = 0.0002

We don't need the nCr function because it tells us that it we want 6 months of success followed by 6 months of failure.  There's only 1 way to do that, so there's nothing to count

For d:  12C6 = 924  

There are 924 different ways to the market can go up 6 times out of 12 months

For e:  (12C2)(0.6^2)(0.4^10) = (66)(0.36)(0.0001) = 0.0025

For f:  Add the following probabilities together...

(12C7)(0.6^7)(q^5) + (12C8)(0.6^8)(q^4) + (12C9)(0.6^9)(q^3)

+ (12C10)(0.6^10)(q^2) + (12C11)(0.6^11)(q^1) + (12C12)(0.6^12)(q^0)

= 0.6652

They are mutually exclusive, the probability for the union is zero because they can't happen at the same time

For g:  Find expected value with the formula E = np  , here n = 12, p = 0.6, so

E = 12(0.6) = 7.8 months

Find the standard deviation with the formula s = √(npq), or s = √(Eq), here q = 0.4, so s = √(7.8(0.4)) = 1.77 months

7 0
3 years ago
simplify the expression by combining the terms, write the terms from highest to the lowest power of the variable 4y^2+y^2-3y-6+1
Artyom0805 [142]
You have to combine like terms.

Like terms are those with the same letters raised to the same power.

These are the sums of the like terms:

1) 4y^2 + y^2 + 14y^2 = 19y^2

2) - 3y + 4y - 7y = - 6y

3) - 6 - 2 = - 8

Simplified expression: 19y^2 - 6y - 8<------------ answer
4 0
3 years ago
Shayla's rideshare fare from the airport was $28.50, and she added a 15% tip. How much did Shayla pay in total
Elodia [21]
15 percent of 28.50 is 4.275
So 28.50 + 4.275 = 32.775
So $32.77
8 0
3 years ago
Evaluate when a = 8 and b = 4. <br><br> ab^2<br> a−b
eduard
<span>Evaluate when a = 8 and b = 4. 

ab^2
a−b


 ab² = (8)(4)² = 8*16= 128

a - b = 8 - 4 = 4 
</span>
3 0
3 years ago
Luke is 5 years younger than 3 times in Sydney's age in the situation what does 3s represnt
Fudgin [204]
3s is 3 times sydneys age. so the equation would be 3s-5
8 0
3 years ago
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