Please help me with this question , thanks so much

The nicotine content in a single cigarette of a particular brand has a distribution with mean 0.4 mg and standard deviation 0.1

a_sh-v [17]

Answer:

Step-by-step explanation:

For this case we can define the random variable of interest as: "The nicotine content in a single cigarette " and for this case we know the following parameters:

$\mu = 0.4, \sigma = 0.1$

And for this case we select a sample size of n =100 and we want to find the following probability:

$P(\bar X$

And for this case we can use the z score formula given by:

$z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z= \frac{0.38-0.4}{\frac{0.1}{\sqrt{100}}}= -2$

And we can find the required probability with the normal standard table and we got:

$P(z$

8 0

3 years ago

Construct a residual plot of the amount of money in a person’s bank account and their age that would indicate a linear model.

stepladder [879]

Answer:

The regression line is not a good model because there is a pattern in the residual plot.

Step-by-step explanation:

Given is a residual plot for a data set

The residual plot shows scatter plot of x and y

The plotting of points show that there is not likely to be a linear trend of relation between the two variables. It is more likely to be parabolic or exponential.

Hence the regression line cannot be a good model as they do not approach 0.

Also there is not a pattern of linear trend.

D) The regression line is not a good model because there is a pattern in the residual plot.

3 0

3 years ago

2. Find the cosine function that is represented in the graph.

Diano4ka-milaya [45]

Answer:

$f(x) = cos(x - \frac{\pi }{4} ) -1$

Step-by-step explanation:

In this graph, we have the coordinate point ( $\frac{\pi }{4} , 0$ ). Without translations, cos(0) = 0, which means that the graph is shifted to the right by $\frac{\pi }{4}$ . We also know that the graph is shifted down by 1 because we have the point

( $\frac{5\pi }{4} , -2$ ), but accounting for the right shift, this point should really by ( $\pi , -2$ ). cos( $\pi$ ) = -1, but on the graph it is -2, meaning that it is shifted down by 1.