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Colt1911 [192]
3 years ago
15

(u-2)(u+6) Simplify your answer.

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0
U with exponent of 2-2u+6
ratelena [41]3 years ago
4 0

Answer:

u^2+4u-12

Step-by-step explanation:

u x u + 6u -2u - 2 x 6

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Avery wants to make a triangular garden but needs to fence it in to keep rabbits out.How can she figure out how much fencing to
nexus9112 [7]
Find the perimeter of the garden find out what kind of triangle the garden is for example if it is a right triangle it has to equal up to 90.

To find the area remember that A=b•h2 as a=area
3 0
3 years ago
Please help me as soon as possible
Alex777 [14]

Answer:

I think the choose (B)

5x/x + 3/x

5 0
3 years ago
Read 2 more answers
What statements describe the properties of a plane? Select three options.
Genrish500 [490]

Answer:

2)A plane has length and width.

3)A plane extends infinitely in all directions

5)A plane is a flat surface.

Step-by-step explanation:

We can think of a plane as a line in space with no height, only length and width.

Yes, a plane is a two-dimensional surface, hence it has length and width.

2)A plane has length and width (TRUE)

The plane surface extends infinitely far, therefore it extends infinitely in all direction.

3)A plane extends infinitely in all directions (TRUE)

5)A plane is a flat surface(TRUE)

The correct options are 2,3 and 5.

See attachment

7 0
3 years ago
Can someone help please it would be greatly appreciated
nikklg [1K]
(y+5) =(5/4)(x-8)
4(y+5)=5(x-8)
4y+20=5x-40
5x-4y=60

Hope that helps you
4 0
3 years ago
What is the midpoint of EC ?
sergij07 [2.7K]

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

7 0
3 years ago
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